Total volume = 80 mL + 20 mL = 100 mL = 0.10 L.
NaOH + HCl ----> NaCl + H2O.
0.08 L * 2.00 mol NaOH/L = 0.16 moles NaOH.
0.02 L * 4.00 mol HCl/L = 0.08 moles HCl.
0.16 - 0.08 = 0.08. There are 0.08 moles NaOH XS.
0.08 moles NaOH produces 0.08 moles OH-.
Concentration OH- = 0.08 moles / 0.10 L = 0.8 M.
Answer:
The value of
is 0.02495.
Explanation:
Initial concentration of
gas = 0.675 M
Initial concentration of
gas = 0.973 M
Equilibrium concentration of mustard gas = 0.35 M

initially
0.675 M 0.973 M 0
At equilibrium ;
(0.675-0.35) M (0.973-2 × 0.35) M 0.35 M
The equilibrium constant is given as :
![K_c=\frac{[S(CH_2CH_2Cl)_2]}{[SCl_2][C_2H_4]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BS%28CH_2CH_2Cl%29_2%5D%7D%7B%5BSCl_2%5D%5BC_2H_4%5D%5E2%7D)


The relation between
and
are :
where,
= equilibrium constant at constant pressure = ?
= equilibrium concentration constant =14.45
R = gas constant = 0.0821 L⋅atm/(K⋅mol)
T = temperature = 20.0°C =20.0 +273.15 K=293.15 K
= change in the number of moles of gas = [(1) - (1 + 2)]=-2
Now put all the given values in the above relation, we get:


The value of
is 0.02495.
173.99cm multiply 68.5 x 2.54 always use that number when converting inches to cm