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Nonamiya [84]
3 years ago
8

When a new bond forms in a chemical reaction, what happens?

Chemistry
2 answers:
Kisachek [45]3 years ago
8 0
The answer to this question would be A. Energy is released. 

When a chemical bond is a form, the bond will either suck up energy or produce energy. So, to be precise the energy is not always released but also can be absorbed. In this case, the energy released number will be a minus.

Options B and C is definitely wrong since the bond is formed by an electron, it won't affects neutron/proton.
Option D might be true since the product is made of 2 or more atoms then it would seem larger. But the size of the actual atom won't be increased.

BabaBlast [244]3 years ago
7 0

ENERGY IS RELEASED IF NEW BONDS ARE FORMED.

<u>Explanation:</u>

When reactants consolidate in substance responses, the bonds between the reactants break by engrossing the vitality which is provided to the reactants at the hour of response and structures results of those reactants which discharge the vitality.

This response is called the exothermic response. When new bonds are formed, higher potential vitality level changes to the lower potential vitality levels. potential vitality is changed over into motor vitality when the bonds break and new bonds are shaped.

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3 years ago
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Identify each of the following mixtures as either homogeneous or heterogeneous and as a solution, a suspension, or a colloid.
Sergeeva-Olga [200]

Blood.

<span>Blood is heterogeneous because it has corpuscles (blood cells and platelets) physically suspended in blood plasma.   Blood plasma and the corpuscles have different properties and can be separated by methods such as centrifugation. Also, blood is considered a colloid suspension because it has the properties of both a colloid and a suspension. This is because the blood plasma acts as a colloid. More so, if blood was left to settle,then the blood cells would collect at the bottom hence taking the characteristic of a suspension. </span>

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3 years ago
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You have 7.86 x 10^23 molecules of NaCl. This would be equal to ___ grams of NaCl.
sergij07 [2.7K]

7.86 \times 10 {}^{23} atoms \\  \frac{7.86}{6.022}  \times  \frac{10 {}^{23} }{ {10}^{23} }   = 1.305\: moles

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3 years ago
Determine the volume in mL of 0.37 M HClO4(aq) needed to reach the half-equivalence (stoichiometric) point in the titration of 2
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14.3mL you require to reach the half-equivalence point

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A strong acid as HClO₄ reacts with a weak base as CH₃CH₂NH₂, thus:

CH₃CH₂NH₂ + HClO₄ → CH₃CH₂NH₃⁺ + ClO₄⁻

As the reaction is 1:1, to reach the equivalence point you require to add the moles of HClO₄ equal to moles CH₃CH₂NH₂ you add originally. Also, half-equivalence point requires to add half-moles of CH₃CH₂NH₂ you add originally.

Initial moles of CH₃CH₂NH₂ are:

20.8mL = 0.0208L × (0.51mol CH₃CH₂NH₂ / 1L) =

0.0106moles CH₃CH₂NH₂

To reach the half-equivalence point you require:

0.0106moles ÷ 2 = 0.005304 moles HClO₄

As concentration of HClO₄ is 0.37M, volume you require to add 0.005304moles is:

0.005304 moles HClO₄ ₓ (1L / 0.37mol) = 0.0143L =

<h3> 14.3mL you require to reach the half-equivalence point</h3>

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