Answer:
Net electric field,
Explanation:
Given that,
Charge 1,
Charge 2,
distance, d = 3.2 cm = 0.032 m
Electric field due to charge 1 is given by :
Electric field due to charge 2 is given by :
The point charges have opposite charge. So, the net electric field is given by the sum of electric field due to both charges as :
So, the electric field strength at the midpoint between the two charges is 91406.24 N/C. Hence, this is the required solution.
Answer:
solved
Explanation:
From the FBD in the attachment we can write that
N+ 80 sin37°= mg
N= 46×g-80×sin37=498.94 N
also, ma= 80×cos37°
a= 80×cos37°/46= 1.3889 m/s^2
also, 10m = 0.5at^2
put a= 1.3889 m/s^2
t= 2.095 secs
d) the speed v =at
v= 1.3889*2.095= 2.91 m/s^2
Answer:
The equivalent resistance of the combination is 3.42 ohms.
Explanation:
We have,
8 ohms resistor is connected in parallel with a 6 ohms resistor. It is required to find the equivalent resistance of this combination.
For a parallel combination, the equivalent resistance is given by :
Plugging the values of R₁ and R₂, we get :
So, the equivalent resistance of the combination is 3.42 ohms.
Answer:
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Answer:
2.49 V.
Explanation:
The formula which relates the equilibrium condition in the electrochemical cell is,
Given that the number of electron is 3 and the value of is 0.652 V.
Now put these values in above equation.
Therefore, the value of Keq for an electrochemical reaction is 2.49 V.