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2 years ago

I NEED HELP!!OMG OMG OMG

Chemistry

2 answers:

Virty [35]2 years ago

7 0

Answer:

AHHHHHHHHHHHHHHHHHH

Explanation:

I WISH I COULD

Eva8 [605]2 years ago

7 0

Winter is purple, spring is blue, summer is orange, fall is green.

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How would you quickly determine whether a cleaning

Leona [35]

Answer:

The answer is explained below

Explanation:

If you add dilute HCl (Hydrochloric Acid) to the solution, and you see fizzing, then it is the carbonate. I would recommend doing this under a fume hood, as HCl has a wicked smell, and can make a few people sick to their stomach (however, you probably won't be using 12M concentrated HCl)

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3 years ago

What two properties most affect the strength of the gravitational forces

goblinko [34]

1) Masses of the object

2) Distance between them

7 0

3 years ago

Read 2 more answers

What is the maximum number of moles of N-acetyl-p-toluidine can be prepared from 70. milliliters of 0.167 M p-toluidine hydrochl

Kitty [74]

Answer:

$\large \boxed{\text{0.012 mol}}$

Explanation:

We will need a balanced equation with moles, so let's gather all the information in one place.

CH₃C₆H₄NH₂·HCl + (CH₃CO)₂O ⟶ CH₃C₆H₄NHCOCH₃ + junk

V/mL: 70.

c/mol·L⁻¹: 0.167

For simplicity in writing , let's call p-toluidine hydrochloride A and N-acetyl-<em>p</em>-toluidine B.

The equation is then

A + Ac₂O ⟶ B + junk

1. Moles of A

$\text{Moles of A} = \text{70. mL A}\times \dfrac{\text{0.167 mmol A}}{\text{1 mL A}}= \text{12 mmol A}$

2. Moles of B

The molar ratio is 1 mol B:1 mol A

Moles of B = moles of A = 12 mmol = 0.012 mol

$\text{You can prepare $\large \boxed{\textbf{0.012 mol}}$ of N-acetyl-p-toluidine. }$

3 0

3 years ago

Q2. Which of the following molecules may show.

jonny [76]

Answer:

I think is answer

CH3cl3

5 0

3 years ago

2. Which pair of elements does not form an ionic bond?

Gekata [30.6K]

$\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}$

Actually Welcome to the concept of Bond Formation.

Answer is :-

B.) O and Cl

These both are Non-Metals with high Electronegativity nature, hence none of them can share electrons to foram any bond to eventually form a Electro valentines Compound.

5 0

3 years ago