Answer:
The pistil and the stamen.
Explanation:
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(a) 43.6 mg; (b) 520 mg
(a) <em>Mass of phosphoric acid (PA) in a dose
</em>
Mass of PA = 2 tsp × (21.8 mg PA/1 tsp) = 43.6 mg PA
(b) <em>Mass of PA in the bottle
</em>
<em>Step 1</em>. Convert <em>ounces to millilitres
</em>
Volume = 4 oz × (30 mL/1 oz) = 120 mL
<em>Step 2.</em> Calculate the mass of PA
Mass of PA = 120 mL × (21.8 mg PA/5 mL) ≈ 520 mg PA
The mass of FeS formed : 11.97 g
<h3>Further explanation</h3>
Reaction
Fe(s) + S(s) → FeS(s)
mass Fe=7.62 g
mol Fe(MW=56 g/mol) :

mass S=8.67 g
mol S(MW=32 g/mol) :

Limiting reactant : smaller ratio(mol:coefficient) ⇒coefficient=1
Fe : S =0.136 : 0.271⇒Fe limiting(smaller), S excess
Mol FeS based on Fe , so mol FeS=0.136
Mass FeS(MW=88 g/mol) :

If the number of valence electron is one than it will be placed in group IA. elements of group IIA will have two valence electrons and so on....