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1 year ago

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do ionic compounds or covalent compounds generally have weaker forces of attraction between the ions or molecules making up the

substance?

1 answer:

Crank1 year ago

7 0

Explanation:

ionic compunds ............

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Write the symbol for the monatomic ion that has a charge of 1– and the condensed electron configuration [ne]3s23p6.

Pani-rosa [81]

<span>Answer is: the symbol is Cl.
[Ne ] 3s</span>² 3p⁶ is electric configuration of noble gas argon, neon (Ne) has10 electrons plus 6 electrons in 3s and 3p orbitals. Neutral atom of m<span>onatomic ion that has a charge of 1– has one electron less than argon, so that atom (chlorine) has 17 electrons. Charge of 1- means one electron more for ion: 17 + 1 = 18.

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2 years ago

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Elements may be individual atoms or they may form molecules. Compounds can only have which form? PLEASE ANSWER FAST WILL GIVE BR

son4ous [18]

Answer:

All compounds are molecules

I got you! i hope i helped

Explanation:

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3 years ago

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Which of the following statements is true regarding soundwaves?

Alexeev081 [22]

Answer: Soundwaves travel as longitudinal or transverse waves depending on the temperature of the medium.

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2 years ago

Balance the following equation:<br> Sg + F2 --> SF

Tanzania [10]

Answer:

S+ F2 ⇒ SF

S=1

F =2

So S +F2 ......... 2SF

2S + F2 ..........2SF this is a balance equation

S=2 F=2 in left side s=2 F = 2 in rightside

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2 years ago

The chemical reaction for the formation of syngas is: CH4 + H2O -> CO + 3 H2 What is the rate for the formation of hydrogen,

grin007 [14]

Answer : The rate for the formation of hydrogen is, 1.05 M/s

Explanation :

The general rate of reaction is,

$aA+bB\rightarrow cC+dD$

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The expression for rate of reaction will be :

$\text{Rate of disappearance of A}=-\frac{1}{a}\frac{d[A]}{dt}$

$\text{Rate of disappearance of B}=-\frac{1}{b}\frac{d[B]}{dt}$

$\text{Rate of formation of C}=+\frac{1}{c}\frac{d[C]}{dt}$

$\text{Rate of formation of D}=+\frac{1}{d}\frac{d[D]}{dt}$

$Rate=-\frac{1}{a}\frac{d[A]}{dt}=-\frac{1}{b}\frac{d[B]}{dt}=+\frac{1}{c}\frac{d[C]}{dt}=+\frac{1}{d}\frac{d[D]}{dt}$

From this we conclude that,

In the rate of reaction, A and B are the reactants and C and D are the products.

a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.

The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.

The given rate of reaction is,

$CH_4+H_2O\rightarrow CO+3H_2$

The expression for rate of reaction :

$\text{Rate of disappearance of }CH_4=-\frac{d[CH_4]}{dt}$

$\text{Rate of disappearance of }H_2O=-\frac{d[H_2O]}{dt}$

$\text{Rate of formation of }CO=+\frac{d[CO]}{dt}$

$\text{Rate of formation of }H_2=+\frac{1}{3}\frac{d[H_2]}{dt}$

The rate of reaction expression is:

$\text{Rate of reaction}=-\frac{d[CH_4]}{dt}=-\frac{d[H_2O]}{dt}=+\frac{d[CO]}{dt}=+\frac{1}{3}\frac{d[H_2]}{dt}$

As we are given that:

$+\frac{d[CO]}{dt}=0.35M/s$

Now we to determine the rate for the formation of hydrogen.

$+\frac{1}{3}\frac{d[H_2]}{dt}=+\frac{d[CO]}{dt}$

$+\frac{1}{3}\frac{d[H_2]}{dt}=0.35M/s$

$\frac{d[H_2]}{dt}=3\times 0.35M/s$

$\frac{d[H_2]}{dt}=1.05M/s$

Thus, the rate for the formation of hydrogen is, 1.05 M/s

6 0

3 years ago