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EleoNora [17]
3 years ago
9

A student lifts a backpack straight up with a force of 53.5 N for a distance of 0.65 m. How much work is done on the backpack?

Physics
2 answers:
gladu [14]3 years ago
8 0

Answer:

W = 34.775J

Explanation:

W = F × d

W = 53.5N × 0.65m

W = 34.775J

W = work = unknown

f = force = 53.5N

d = distance = 0.65m

Semenov [28]3 years ago
3 0
The answer is 34.775j because w=Fd (53.5N)(0.65m)=34.775j
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Electric field strength = resistivity of copper x current density
where
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diameter = 2.05mm=.00205 m
current = 2.75 A
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find the cross section area
cross section area = pi.(d/2)^2;  
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Electric field stregnth =1.72 x 10^-8 ohm meter x 35.55 x10^2 A/m^2
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The electric field strength of copper is 46.415 V/m.


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3 years ago
A very strong, but inept, shot putter puts the shot straight up vertically with an initial velocity of 11.0 m/s. how long does h
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The shot putter should get out of the way before the ball returns to the launch position.

Assume that the launch height is the reference height of zero.
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The time when the ball is at the reference position (of zero) is given by
ut - (1/2)gt² = 0
11t - 0.5*9.8t² = 0
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t = 0 corresponds to when the ball is launched.
t = 0.45 corresponds to when the ball returns to the launch position.

Answer: 0.45 s
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Explanation:

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Hope this helped!
5 0
4 years ago
According to a rule-of-thumb. every five seconds between a lightning flash and the following thunder gives the distance to the f
Bond [772]

Answer:

S_{s}=300 m/s

The rule for kilometers is that every three seconds between a lightning flash and the following thunder gives the distance to the flash in kilometers.

Explanation:

In order to use the rule of thumb to find the speed of sound in meters per second, we need to use some conversion ratios. We know there is 1 mile per every 5 seconds after the lightning is seen. We also know that there are 5280ft in 1 mile and we also know that there are 0.3048m in 1ft. This is enough information to solve this problem. We set our conversion ratios like this:

\frac{1mi}{5s}*\frac{5280ft}{1mi}*\frac{0.3048m}{1ft}=321.87m/s

notice how the ratios were written in such a way that the units got cancelled when calculating them. Notice that in one ratio the miles were on the numerator of the fraction while on the other they were on the denominator, which allows us to cancel them. The same happened with the feet.

The problem asks us to express the answer to one significant figure so the speed of sound rounds to 300m/s.

For the second part of the problem we need to use conversions again. This time we will write our ratios backwards and take into account that there are 1000m to 1 km, so we get:

\frac{5s}{1mi}*\frac{1mi}{5280ft}*\frac{1ft}{0.3048m}*\frac{1000m}{1km}=3.11s/km

This means that for every 3.11s there will be a distance of 1km from the place where the lightning stroke. Since this is a rule of thumb, we round to the nearest integer for the calculations to be made easily, so the rule goes like this:

The rule for kilometers is that every three seconds between a lightning flash and the following thunder gives the distance to the flash in kilometers.

3 0
3 years ago
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