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inn [45]
3 years ago
10

If 8.87 grams of phosphorus react with 11.43 grams of oxygen, what is the empirical fr pound formed?

Chemistry
2 answers:
Alinara [238K]3 years ago
6 0

\boxed{\begin{array}{c|c|c|c|c}\boxed{\sf Element}&\boxed{\sf Mass\:in\: compound}&\boxed{\sf No\:of\:moles}&\boxed{\sf Ratio}&\boxed{\sf Simplified\:ratio}\\ \sf P &\sf 8.87g &\sf \dfrac{8.87}{31}=0.28&\sf \dfrac{0.28}{0.28}=1&\sf 1 \\ \sf O&\sf 11.43g &\sf \dfrac{11.4}{16}=0.71 &\sf \dfrac{0.71}{0.18}=3.9&\sf 4\\ \end{array}}

Empirical formula:-

\\ \sf\longmapsto PO_4

777dan777 [17]3 years ago
3 0

Answer: Phosphorus 3143.58=1.4 1

Oxygen 1656.42=3.5 2.5

Explanation:

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<em><u>calculation</u></em>

energy is calculate  MCΔT  formula  where,

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