Answer and Explanation:
Data provided in the question
Force = 50N
Length = 5mm
diameter = 2.0m =
Extended by = 0.25mm =
Based on the above information, the calculation is as follows
a. The Stress of the wire is
here area of circle = perpendicular to the are i.e cross-sectional i.e
=
=
Now place these above values to the above formula
= 15.92 MPa
As 1Pa = 1 by N m^2
So,
MPa = 10^6 N m^2
b. Now the strain of the wire is
=
Answer:
20654 N
Explanation:
Applying
F = kqq'/r²........... equation 1
Where F = Force between the charge, q = First charge, q' = second charge, r = distance betweeen the charge, k = coulomb's constant.
From the question,
Given: q = -0.0004 C, q' = 0.00092 C, r = 0.4 m
Constanr: k = 8.98×10⁹ Nm²/C²
Substitute these values into equation 1
F = ( -0.0004×0.00092×8.98×10⁹)/(0.4²)
F = (3.30464×10³)/0.16
F = (3304.64)/0.16
F = 20654 N
Hence the force between the charges is 20654 N
Answer:
The electrostatic force will remain the same
Explanation:
From the question we are told that
The charge on the each conducting sphere is
The radius each sphere is
Generally electrostatic force between the sphere is mathematically represented as
Here k is the coulomb constant ,
d is the distance between the two sphere which is measured from one center of the sphere to the other center of the sphere
Now from the question we are told that the radius of the spheres is doubled (i.e from 0.10 m to 0.2 m ) , this will not affect the distance between the sphere because their center are still in the same position
and given there is no change in the distance between the spheres , the electrostatic force will remain the same
1. Find the force of friction between the sports car and the station wagon stuck together and the road. The total mass m = 1928kg + 1041kg = 2969kg. The only force in the x-direction is friction: F = μ*N = μ * m * g
2. Find the acceleration due to friction:
F = m*a = μ * m * g => a = μ * g = 0.6 * 9.81
3. Find the time it took the two cars stuck together to slide 12m:
x = 0.5*a*t²
t = sqrt(2*x / a) = sqrt(2 * x / (μ * g) )
4. Find the initial velocity of the two cars:
v = a*t = μ * g * sqrt(2 * x / (μ * g) ) = sqrt( 2 * x * μ * g)
5. Use the initial velocity of the two cars combined to find the velocity of the sports car. Momentum must be conserved:
m₁ mass of sports car
v₁ velocity of sports car before the crash
m₂ mass of station wagon
v₂ velocity of station wagon before the crash = 0
v velocity after the crash
m₁*v₁ + m₂*v₂ = (m₁+m₂) * v = m₁*v₁
v₁ = (m₁+m₂) * v / m₁ = (m₁+m₂) * sqrt( 2 * x * μ * g) / m₁
v₁ = 33.9 m/s
Answer:
C: one
Explanation: One .methane molecule should be added to the reactants side to balance the equation and obey the law of conservation of matter.