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3 years ago

Why are benzene rings more stable than alkenes?

1 answer:

7 0

The six carbon atoms form a perfectly regular hexagon. All of the carbon-carbon bonds have exactly the same lengths - somewhere between single and double bonds. There are delocalized electrons above and below the plane of the ring, which makes benzene particularly stable.

You might be interested in

What ratio of nitrogen and hydrogen molecules would result in no left-over reactants? Explain your answer.

madam [21]

A ration, Nitrogen to Hydrogen, of 1 : 3 would result in no left-over reactants

Explanation:

This is because Nitrogen and Hydrogen would react to form ammonia as shown in the following reaction below;

N₂ (g) + 3H₂ (g) → 2NH₃ (g)

For every mole of Nitrogen gas, you would require 3 moles of Hydrogen gas. This way they would react to form Ammonia with no leftover reactants.

Learn More:

For more on balanced gas reaction equations check out;

brainly.com/question/3407131

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#LearnWithBrainly

6 0

3 years ago

Using spectroscopic notation write the complete electron configuration for the fluorine atom. Using noble gas notation write the

prohojiy [21]

Explanation:

Flourine has atomic number of 9 and hence 9 electrons in its neutral state. The full electronic configuration is given as;

1s2 2s2 2p5

Carbon has atomic number of 6 and hence 6 electrons in it's neutral state. The noble gas notation as the following format;

[closest noble gas before the element] remaining electrons

The nearest noble gas to carbon is Helium, the noble gas notation is given as;

[He] 2s4

3 0

3 years ago

What is the final volume of NaOH solution prepared from 100.0 mL of 0.500 M NaOH if you wanted the final concentration to be 0.1

suter [353]

Answer:

The final volume of NaOH solution is 30ml

Explanation:

We all know that

V1S1 = V2S2

or V1= V2S2÷S1

or V1= V2×S2×1/S1

or V1=100×0.15×1/0.50

V1= 30

∴30 ml NaOH solution is required to prepare 0.15 M from 100ml 0.50 M NaOH solution.

5 0

3 years ago

When a solution containing 1.4000 g of Ba(NO3)2 and 2.4000 g of HSO3NH2 is boiled, a precipitate forms. One possible identity fo

Georgia [21]

Answer:

See explanation for detailed solution

Explanation:

The balanced reaction equation is Ba(NO3)2 + 2HSO3NH2 → Ba(SO3NH2)2 + 2HNO3

Number of moles of Ba(NO3)2 = 1.4 g/ 261.337 g/mol = 5.36 × 10^-3 moles

From the reaction equation;

1 mole of Ba(NO3)2 yields 1 mole of Ba(SO3NH2)2

5.36 × 10^-3 moles of Ba(NO3)2 yields 5.36 × 10^-3 moles of Ba(SO3NH2)2

For HSO3NH2

Number of moles = 2.4g/97.10 g/mol =0.0247 moles

2 moles of HSO3NH2 yields 1 mole of Ba(SO3NH2)2

0.0247 moles of HSO3NH2 yields 0.0247 ×1/2 = 0.0137 moles

Hence, Ba(NO3)2 is the limiting reactant

The theoretical yield of Ba(SO3NH2)2 is 5.36 × 10^-3 moles × 329.4986 g/mol = 1.766 g

Number of moles = mass/ molar mass

Molar mass = mass/ number of moles

Molar mass = 1.6925 g/5.36 × 10^-3 moles = 315.76 g

3 0

4 years ago

What does I stand for?

tatuchka [14]

I: Current
V: Voltage
R: resistance
you’re welcome ;)

7 0

3 years ago

Read 2 more answers