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sergey [27]
3 years ago
7

What is the maximum number of electrons in the following energy level? n = 1

Chemistry
1 answer:
Lyrx [107]3 years ago
4 0

Maximum number of electrons in nth energy level

\\ \sf\longmapsto 2n^2

Now

  • n=1

Max electrons

\\ \sf\longmapsto 2(1)^2

\\ \sf\longmapsto 2e^-

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If a pea plant is tall, and tallness in pea plants is dominant over shortness, what is the phenotype of the pea plant?
Firlakuza [10]

Answer:

The height of the plant is controlled by two alleles - the dominant 'T' for tallness and recessive 't' for shortness of the plant. The dominant allele represses the expression of the recessive allele. The recessive allele is expressed only in the homozygous state (tt)

6 0
3 years ago
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A bike lost 20% of its value after the first year, its value after the first year is $1039. Calculate the original price of the
musickatia [10]

Answer:

$1246.90

Explanation:

Since the bike lost 20%% of it's value and it now currently at $$1039, we have to do 20% * $1039 to find the amount of money lost. 20%*1039=207.8. We have to add it up to find the original value so 1039+207.8=$1246.8

6 0
3 years ago
The atmosphere's variable gases that most influence the greenhouse effect are _____. nitrogen and oxygen argon and carbon dioxid
Katena32 [7]
The correct answer is carbon dioxide and water vapor

These negative gasses get modified and then remain in the atmosphere without the possibility of leaving, which is why the greenhouse effect occurs.
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3 years ago
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What is the effect of this??
a_sh-v [17]

Answer:

Explanation:

The wavelength is the distance between two adjacent wavefronts. ... If the wave crosses to the new medium at an angle (not 90 degrees), the change ... When light enters a more optically dense medium, it is refracted closer to the normal. the same as the critical angle, light will travel along the boundary of the 2 mediums.

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3 years ago
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If you start with 0.30 m mn2 , at what ph will the free mn2 concentration be equal to 4.6 x 10-11 m?
aksik [14]

If you start with 0.30 m Mn₂ , at 12.5 pH, free Mn₂ concentration be equal to 4.6 x 10⁻¹¹ m

Initial molarity of Mn₂ = 0.30 M

Final molarity of Mn₂ = 4.6 x 10⁻¹¹

pH = ?

Ksp [Mn(OH)₂] = 4.6 x 10⁻¹⁴ (standard value)

Write the ionic equation

    Mn(OH)₂   →    Mn⁺² + 2OH⁻

    [Mn⁺²] = 4.6 x 10⁻¹¹

We will calculate the concentration of OH⁻ by using Ksp expression

    Ksp = [Mn⁺²][OH-]²

    [Mn⁺²][OH⁻]² = 4.6 x 10⁻¹⁴

    [OH⁻]² = 4.6 x 10⁻¹⁴ / 4.6 x 10⁻¹¹

    [OH⁻]² = 10⁻³

    [OH⁻] = (10⁻³)¹⁽²

    [OH⁻] = 0.0316 M

Calculate the pOH

    pOH = -log [OH⁻]

    pOH =  -log [0.0316]

    pOH = 1.5

Now calculate pH

   pH = 14 - pOH

   pH = 14 - 1.5

   pH = 12.5

You can also learn about molarity from the following question:

brainly.com/question/14782315

#SPJ4

7 0
1 year ago
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