All categories

2 years ago

Which one is NOT a monomial

Mathematics

2 answers:

lesantik [10]2 years ago

7 0

<h3>Answer: Choice A</h3>

This is because 3x-4 is a binomial consisting of the two terms 3x and -4

A monomial has only one term, which choices B through D reflect that.

Valentin [98]2 years ago

3 0

A because it’s a binomial

You might be interested in

if your answer is "No," how much more lacquer does she need? if your answer is "yes," how much lacquer will she have left over?

babunello [35]

my answer is no ,yes ,no

So ,maybe u find the answer

Step-by-step explanation:

if your answer is "No," how much more lacquer does she need? if your answer is "yes," how much lacquer will she have left over?AND if it is also no ,yes , no...show your work to justify your answer.

3 0

3 years ago

Help, please<br> A: 2<br> B: -2<br> C: 1/2<br> D:-1/2

Anna [14]

Answer:

$\left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \int\limits^a_b {x} \, dx \geq \sqrt{x} \left \{ {{y=2} \atop {x=2}} \right. \frac{x}{y} \alpha \alpha \alpha =\beta$

Step-by-step explanation:

4 0

3 years ago

Given a = -3, b = 5, and c = -8, then a 2 b + c is _____.<br><br> -38<br> -53<br> 37<br> 22

AnnyKZ [126]

This is how you would arrive to the answer 37

4 0

3 years ago

Read 2 more answers

I’m lost again can somebody help asap ??

serious [3.7K]

Fully detailed and equipped information process right below. The answer for this question is "25" (simplified form).

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(5^{- 5} \times 2^8 \times 1 \Bigg)^{- 2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(2^8 \times 1 \times \dfrac{1}{5^5} \Bigg)^{- 2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(1 \times \dfrac{2^8 \times 1}{5^5} \Bigg)^{- 2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(1 \times \dfrac{256}{3125} \Bigg)^{- 2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(\dfrac{3125}{256} \Bigg)^2}$

$\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \dfrac{3125^2}{256^2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{1}{2^3 \times 5^2} \Bigg)^4 \times \dfrac{3125^2}{256^2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{1^4}{(2^3 \times 5^2)^4} \Bigg) \times \dfrac{3125^2}{256^2}}$

$\mathbf{2^{28} \times \Bigg(\dfrac{1^4}{(5^2)^4 \times (2^3)^4} \Bigg) \times \dfrac{3125^2}{256^2}}$

$\mathbf{2^{28} \times \dfrac{1}{2^{12} \times 5^8} \times \dfrac{3125^2}{256^2}}$

$\mathbf{\dfrac{3125^2 \times 1 \times 2^{28}}{256^2 \times 5^8 \times 2^{12}}}$

$\mathbf{\dfrac{2^{(28 - 12)} \times 3125^2}{256^2 \times 5^8}}$

$\mathbf{\dfrac{2^{16} \times 3125^2}{256^2 \times 5^8}}$

$\mathbf{\dfrac{2^{16} \times (5^5)^2}{(2^8)^2 \times 5^8}}$

$\mathbf{\dfrac{2^{16} \times 5^{10}}{2^{16} \times 5^8}}$

$\mathbf{\dfrac{2^{16} \times 5^{10 - 8}}{2^{16}}}$

$\mathbf{\dfrac{5^{10 - 8}}{1}}$

$\mathbf{\therefore \quad 5^2}$

$\mathbf{\therefore \quad 25}$

$\boxed{\mathbf{\underline{\therefore \quad Final \: \: Answer \: \: is: \: 25}}}$

Hope it helps.

7 0

3 years ago

What scenario could be modeled by the graph below?

Dafna1 [17]

Answer:

I would believe that it is A.

Step-by-step explanation:

The fact that A has 5, and x is minus two times, 5/2= 2.5, and that is where the second arrowhead is pointing to on the x axis.

6 0

3 years ago