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yulyashka [42]
2 years ago
7

Which one is NOT a monomial

Mathematics
2 answers:
lesantik [10]2 years ago
7 0
<h3>Answer: Choice A</h3>

This is because 3x-4 is a binomial consisting of the two terms 3x and -4

A monomial has only one term, which choices B through D reflect that.

Valentin [98]2 years ago
3 0
A because it’s a binomial
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What is the most accurate name for the polygon shown in the figure
frutty [35]
Irregular hexagon/polygon
8 0
3 years ago
F(x)= 3x-3, g(x) =5x-9 find (f-g)(x)
marusya05 [52]

Answer:

Step-by-step explanation:

The answer is A

6 0
3 years ago
A report indicated that 37% of adults had received a bogus email intended to steal personal information. Suppose a random sample
fiasKO [112]

Answer:

5.05% probability that no more than 34% had received such an email.

Step-by-step explanation:

We use the binomial approximation to the normal to solve this problem.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 700, p = 0.37

\mu = E(X) = np = 700*0.37 = 259

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{700*0.37*0.63} = 12.77

In a random sample of 700 adults, what is the probability that no more than 34% had received such an email?

34% is 0.34*700 = 238

So this probability is the pvalue of Z when X = 238.

Z = \frac{X - \mu}{\sigma}

Z = \frac{238 - 259}{12.77}

Z = -1.64

Z = -1.64 has a pvalue of 0.0505

5.05% probability that no more than 34% had received such an email.

7 0
4 years ago
Plz help will be thanked and will pick out brainly
vlabodo [156]
B is your answer
Hope this helps:D
have a great rest of a brainly day!
8 0
3 years ago
A copy machine can print 480 copies every 4 minutes.<br> How many copies can it print in 10 minutes?
Irina-Kira [14]

Step-by-step explanation:

So you need to figure out how much it can print in 1 minute. You can find that out by dividing 480 by 4. You get 120 which you then multiple by 10.

So the answer is 1,200

6 0
4 years ago
Read 2 more answers
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