(a) The compression of the spring is 0.074 m.
(b) The potential energy of block will be converted to elastic potential energy of the spring when the block comes to rest.
<h3>
Compression of the spring [ x ]</h3>
The compression of the spring is calculated as follows;
F = kx
mg = kx
x = mg/k
where;
- m is mass of the object
- k is the spring constant
x = (3 x 9.8) / (400)
x = 0.074 m
<h3>Motion of the block</h3>
Based on the principle of conservation of energy, the potential energy of block will be converted to elastic potential energy of the spring when the block comes to rest.
Learn more about elastic potential energy here: brainly.com/question/25996974
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Answer:
Below is the calculation of all the required quantities. From the calculations, Vx must change, the velocity before hitting the ground must change and the angles also must change.
Explanation:
Below is an attachment that contains the calculation steps.
Thank you for reading.
Answer:
so am i ._. 15 not 1 ofc lol
Explanation:
Answer:
2.7s
Explanation:
The solution of time required is shown below:-
In the RC circuit condenser charge 63 percent of the full charge from initial time to constant time
Now, the
63% that is equal to 0.63 which is full equilibrium charge
Therefore, the time required to maintain will be Equal to time (t) constant that is 2.7s
So, the correct answer is 2.7s
Answer:
b) 472HZ, 408HZ
Explanation:
To find the frequencies perceived when the bus approaches and the train departs, you use the Doppler's effect formula for both cases:

fo: frequency of the source = 440Hz
vs: speed of sound = 343m/s
vo: speed of the observer = 0m/s (at rest)
v: sped of the train
f: frequency perceived when the train leaves us.
f': frequency when the train is getTing closer.
Thus, by doing f and f' the subjects of the formulas and replacing the values of v, vo, vs and fo you obtain:

hence, the frequencies for before and after tha train has past are
b) 472HZ, 408HZ