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3 years ago

Transpiration is evaporation from plants. True False

Physics

2 answers:

horsena [70]3 years ago

8 0

Answer:

Ur answer is true :D

Explanation:

Transpiration is just a subset of the evaporation process, and it's the water that is inside plants, and then when that evaporates and moves into the atmosphere, that process is called transpiration.

Hope this helps!!

boyakko [2]3 years ago

3 0

Answer:

True

Explanation:

"Transpiration is just a subset of the evaporation process"

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The formation of atp as a result of the activity of the electron transport system is termed substrate-level phosphorylation is c

Zigmanuir [339]

Answer:

Oxidative phosphorylation

Explanation:

This takes place mostly in the organelle called the mitochondrion.

Oxidation of nutrients in cells by enzymes results in the release of the chemical energy present in the molecular energy.

The NADH and succinate products of the citric acid cycle are also oxidized. All this series of reactions takes place in the Electron transport system.The energy from the oxidation is used to produce adenosine triphosphate (ATP) hence the name oxidative phosphorylation.

4 0

3 years ago

The average threshold of dark-adapted (scotopic) vision is 4.00 10-11 W/m2 at a central wavelength of 500 nm. If light with this

Studentka2010 [4]

Answer:

E = h f = h c / λ energy of single photon

n E = 4.00E-11 W/m^2 energy required for visibility

n h c / λ = 4.00E-11 number of photons required for visibility (per square meter)

n = 4.00E-11 * 5.00E-7 / (6.63E-34 * 3.00E8)

n = 20.0E-18 / 19.9 E-26 = 1.00E8

100 million photons would be required on 1 m^2 to create visibility

a / A = π * (3.6E-3)^2 / 1 = 4.07E-5 fraction of area available

4.07E-5 * 1.00E8 = 4.07E3 photons required

8 0

2 years ago

A parallel plate capacitor is constructed with a dielectric slab with κ = 1.5 inserted between the plates. The area of each plat

maksim [4K]

Answer:

The value is $V = 4.533 \ V$

Explanation:

From the question we are told that

The dielectric constant is k = 1.5

The area of each plate is $A = 5 \ cm^2 = 0.0005 m^2$

The distance between the plates is $d= 1 \ mm = 0.001 \ m$

The charge on the capacitor is $Q = 6*10^{-11} \ C$

Generally the electric field in a vacuum is mathematically represented as

$E_o = \frac{V_o}{d}$

Generally $V_o$ is the voltage of the capacitor which is mathematically represented as

$V_o = \frac{Q}{C_o}$

Here $C_o$ is the capacitance of the capacitor in a vacuum which is mathematically represented as

$C_o = \frac{\epsilon_o * A}{d}$

Here $epsilon_o$ is a constant with value $epsilon_o= 8.85*10^{-12} C^2 \cdot N^{-1} \cdot m^{-2}$

=> $C_o = \frac{8.85*10^{-12} * 0.0005 }{0.001}$

=> $C_o = 4.425 *10^{-12} \ F$

$V_o = \frac{6*10^{-11} }{ 4.425 *10^{-12}}$

$V_o = 13.6 \ V$

$E_o = \frac{ 13.6}{0.001}$

=> $E_o = 13600 \ V/m$

The electric field when the dielectric slab is inserted is mathematically represented as

$E = \frac{E_o}{k}$

=> $E = \frac{13600}{1.5}$

=> $E =9067 \ V/m$

Generally the electric field between the plates is mathematically evaluated as

$E_{N} = E_o - E$

=> $E_{N} = 13600- 9067$

=> $E_{N} = 4533 \ V/m$

Generally the potential difference between the plates is

$V = 4533 * 0.001$

=> $V = 4.533 \ V$

6 0

4 years ago

A magnetic field of 37.2 t has been achieved at the mit francis bitter national magnetic laboratory. Find the current needed to

jeka57 [31]

Answer:

Here is the complete question:

https://www.chegg.com/homework-help/questions-and-answers/magnetic-field-372-t-achieved-mit-francis-bitter-national-magnetic-laboratory-find-current-q900632

a) Current for long straight wire $=3.7\ MA$

b) Current at the center of the circular coil $=2.48\times 10^{5}\ A$

c) Current near the center of a solenoid $236.8\ A$

Explanation:

⇒ Magnetic Field due to long straight wire is given by (B),where $B=\frac{\mu\times I}{2\pi(r) },so\ I=\frac{B\ 2\pi(r)}{\mu}$

$\mu=4\pi \times 10^{-7}\ \frac{henry}{m}$

Plugging the values,

Conversion $1\times 10^6 A = 1\ MA$ ,and $2cm=\frac{2}{100}=0.02\ m$

$I=\frac{37.2\times \ 2\pi(0.02)}{4\ \pi \times (10^{-7})}=3.7\ MA$

⇒Magnetic Field at the center due to circular coil (at center) is given by, $B=\frac{\mu\times I (N)}{2(a)}$

So $I= \frac{2B(a)}{\mu\ N} = \frac{2\times 37.2\times 0.42}{4\pi\times 10^{-7}\times 100}=2.48\time 10{^5}\ A$

⇒Magnetic field due to the long solenoid, $B=\mu\ nI=\mu (\frac{N}{l})I$

Then $I=\frac{B}{\mu(\frac{N}{L})} \approx 236.8\A$

So the value of current are $3.7 MA$ , $2.48\times 10^{5} A$ and $236.8\ A$ respectively.

8 0

3 years ago

A cork floats on the surface of an incompressible liquid in a container exposed to atmospheric pressure. The container is then s

yaroslaw [1]

Question:

A cork floats on the surface of an incompressible liquid in a container exposed to atmospheric pressure. The container is then sealed and the air above the liquid is evacuated. The cork:

A. sinks slightly

B. rises slightly

C. floats at the same height

D. bobs up and down about its old position

Answer:

The correct answer is C) floats at the same height

Explanation:

The liquid is incompressible because its density very high and leaves no room for further compaction whether or not there is atmospheric pressure. So when you put a cork on the liquid, pressure or no pressure, there is no displacement hence it floats on the same height regardless of the absence of air.

Cheers!

6 0

3 years ago