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k0ka [10]
3 years ago
6

At 1.3 atm and 23 degrees Celsius, 12.5 grams of a gas occupies a volume of 8.2 liters. What is the molar mass (grams/mole) of t

he gas?
Chemistry
1 answer:
klemol [59]3 years ago
7 0

Answer:

0.44 moles Molar Mass = 28.496

Explanation:

1.3(8.2)=n(0.0821)(23+273)

PV=nRT

12.5/0.43865

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Part 1. A chemist reacted 12.0 liters of F2 gas with NaCl in the laboratory to form Cl2 gas and NaF. Use the ideal gas law equat
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The mass of NaCl needed for the reaction is 91.61 g

We'll begin by calculating the number of mole of F₂ that reacted.

  • Volume (V) = 12 L
  • Temperature (T) = 280 K
  • Pressure (P) = 1.5 atm
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18 = n × 22.988

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From the balanced equation above,

1 mole of F₂ reacted with 2 moles of NaCl.

Therefore,

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Mass = mole × molar mass

Mass of NaCl = 1.566 × 58.5

Mass of NaCl = 91.61 g

Therefore, the mass of NaCl needed for the reaction is 91.61 g

Learn more about stiochoimetry: brainly.com/question/25830314

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