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lawyer [7]
3 years ago
13

Describe an experiment to verify the principle of moments

Physics
1 answer:
Ludmilka [50]3 years ago
5 0

The principle of moment can be verified when two known masses are suspended on a uniform meter rule.

<h3>What is principle of moment?</h3>

The principle of moment states that, the sum of clockwise moment is equal to the sum of the anticlockwise moment.

The principle of moment is verified when two known mass (m1 and m2) are suspended on a uniform meter rule.

The clockwise moment will be equal anticlockwise moment of the two masses.

(m_1g )r_1 = (m_2g)r_2

Thus, the principle of moment can be verified when two known masses are suspended on a uniform meter rule.

Learn more about principle of moment here: brainly.com/question/20298772

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Hope it helps u! :)

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Can a physical guantity have unit but is dimensionless ?
Goshia [24]
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3 years ago
Jon and Jim push a dead car forward to the gas station. Jon pushes with 90N while Jim pushes 80 N.
Nina [5.8K]

The resultant of the two forces is about 170 N.

<h3>What is the resultant force?</h3>

The term resultant force has to do with the single force that has the same magnitude and direction as two or more forces acting together.

In this case, the both forces are acting in the forward direction. This implies that the resultant force is 90 N  + 80 N = 170 N.

Learn more about resultant force:brainly.com/question/16380983

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2 years ago
An α-particle has a charge of +2e and a mass of 6.64 × 10-27 kg. It is accelerated from rest through a potential difference that
zzz [600]

Answer with Explanation:

We are given that

Charge on alpha particle=q=2 e=2\times 1.6\times 10^{-19} C

1 e=1.6\times 10^{-19} C

Mass of alpha particle=m=6.64\times 10^{-27} kg

Potential difference,V=1.97\times 10^6 V

Magnetic field,B=3.49 T

a.Speed of alpha particle=v=\sqrt{\frac{2 qV}{m}}

By using the formula

v=\sqrt{\frac{2\times 2\times 1.6\times 10^{-19}\times 1.97\times 10^6}{6.64\times 10^{-27}}

v=1.38\times 10^7 m/s

b.Magnetic force,F=qvB=2\times 1.6\times 10^{-19}\times 1.38\times 10^7\times 3.49=1.5\times 10^{-11} N

F=1.5\times 10^{-11} N

c.Radius of circular path, r=\frac{mv^2}{F}

r= \frac{6.64\times 10^{-27}\times (1.38\times 10^7)^2}{1.5\times 10^{-11}}

r=0.084 m

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3 years ago
How to make a force field for your house
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That is not yet possible. that technology has not yet been invented.
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