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2 years ago

How is the jet stream Influencing the weather conditions depicted on the map?

Chemistry

1 answer:

Sauron [17]2 years ago

4 0

Answer:

B. The jet stream is causing cold fronts to move from east to west

Explanation:

I hope this helped!

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compound 1 contains 15.0g of hydrogen and 120.0g oxygen. What is the percent compound of each element?

allsm [11]

Note down the formula below

$\boxed{\sf Mass\%\;of\; element=\dfrac{Mass\:of\:the\: element}{Mass\;of\:the\: compound}\times 100}$

Mass of the compound

$\\ \sf\longmapsto 15+120=135g$

Mass % of Hydrogen:-

$\\ \sf\longmapsto \dfrac{15}{135}\times 100$

$\\ \sf\longmapsto \dfrac{1}{9}\times 100$

$\\ \sf\longmapsto 11.1\%$

Mass % of Oxygen:-

$\\ \sf\longmapsto \dfrac{120}{135}\times 100$

$\\ \sf\longmapsto \dfrac{8}{9}\times 100$

$\\ \sf\longmapsto 88.9\%$

8 0

3 years ago

: An unknown metal crystallizes in the cubic crystal structure. The metal has a radius 140pm, atomic mass of 135 g/mol, and dens

ki77a [65]

The cubic unit cell this metal crystallize as is BCC structure .

The structure of a crystalline solid, whether a metal or not, is best described by considering its simplest repeating unit, which is referred to as its unit cell.

The unit cell consists of lattice points that represent the locations of atoms or ions.

The entire structure then consists of this unit cell repeating in three dimensions

$\rm \rho =\dfrac{nM}{N_{0} a^{3}} \\\\\\\\\rm n =\dfrac{\rho N_{0} a^{3}}{M} \\\\\\\\Assuming\; it \; to \; be \; a\; BCC\; structure \\\\\\ r = \dfrac{\sqrt{3} \times a}{4} \\\\\\Therefore\; a = 3.23 \times 10^{-8}\\\\\\\\\rm n =\dfrac{13.3 \times 6.022 \times 10^{23}\times 3.23^{3}\times (10^{-8})^{3}}{135} \\\\$

n= 2

Hence our assumption was correct

It is a BCC structure .

Therefore the cubic unit cell this metal crystallize as is BCC structure .

To know more about unit cell

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5 0

1 year ago

1. Fill in the blanks. Example: A nitrogen atom takes on a 3- charge when it forms an anion and becomes nitride. a. A magnesium

Tema [17]

Answer: a. +2, cation and magnesium ion .

b. -1, anion, chloride

c. -2, anion, oxide

d. +1. cation , potassium ion

Explanation:

When an atom accepts an electron negative charge is created on atom and is called as anion.

When atom loses an electron positive charge is created on atom and is called as cation.

Magnesium (Mg) with atomic number of 12 has electronic configuration of 2,8,2 and thus it can lose 2 electrons to form $Mg^{2+}$ cation and becomes magnesium ion.

Chlorine (Cl) with atomic number of 17 has electronic configuration of 2,8,7 and thus it can gain 1 electron to form $Cl^{-}$ anion and becomes chloride.

Oxygen (O) with atomic number of 8 has electronic configuration of 2,6 and thus it can gain 2 electrons to form $O^{2-}$ anion and becomes oxide.

Potassium (K) with atomic number of 19 has electronic configuration of 2,8,8,1 and thus it can lose 1 electron to form $K^{+}$ cation and becomes potassium ion.