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3 years ago

How is the jet stream Influencing the weather conditions depicted on the map?

Chemistry

1 answer:

Sauron [17]3 years ago

4 0

Answer:

B. The jet stream is causing cold fronts to move from east to west

Explanation:

I hope this helped!

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Which of the elements must be available in water for the metamorphosis of tadpoles?

Grace [21]

The element iodine (I) is important for the fast and hastened metamorphosis of frog-tadpoles. As amphibians, the tadpoles can live in water and land but when they are born they are iodine-deficient. Tadpoles that do not receive ample amount of iodine become tadpoles until the end of their days.

8 0

3 years ago

If a bag of peas weighs 454 grams, how many peas would be in the bag?

OverLord2011 [107]

In a bag of peas that weighs 454 grams, there are between 1261 and 4540 peas.

The average pea weighs between 0.1 and 0.36 grams.

If we take the lower value (0.1 g/pea), the number of peas in 454 g is:

$454 g \times \frac{1pea}{0.1 g} = 4540pea$

If we take the higher value (0.36 g/pea), the number of peas in 454 g is:

$454 g \times \frac{1pea}{0.36 g} \approx 1261pea$

In a bag of peas that weighs 454 grams, there are between 1261 and 4540 peas.

You can learn more about conversion factors here: brainly.com/question/1844638

6 0

3 years ago

A 800N mountain climber scales a 160m cliff. How much work is done by the mountain climber?

Fittoniya [83]

Answer:

Work done, W = 128 kJ

Explanation:

Given that,

Weight of a mountain climber, F = 800 N

It climbs to a cliff that is 160 m high.

We need to find the work done by the mountain climber. The work done by an object is given by the formula as follows :

W = Fd

Put the values of F and d.

W = 800 N × 160 m

W = 128000 J

W = 128 kJ

So, 128 kJ of work is done by the mountain climber.

3 0

3 years ago

A sample of argon gas has a volume of 795 mL at a pres-sure of 1.20 atm and a temperature of 116 ∘C. What is the final volume of

jek_recluse [69]

<u>Answer:</u> The volume when the pressure and temperature has changed is $1.6\times 10^2mL$

<u>Explanation:</u>

To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law.

The equation follows:

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1,V_1\text{ and }T_1$ are the initial pressure, volume and temperature of the gas

$P_2,V_2\text{ and }T_2$ are the final pressure, volume and temperature of the gas

Let us assume:

$P_1=1.20atm\\V_1=795mL\\T_1=116^oC=[116+273]K=389K\\P_2=0.55atm\\V_2=?mL\\T_2=75^oC=[75+273]K=348K$

Putting values in above equation, we get:

$\frac{1.20atm\times 795mL}{389K}=\frac{0.55atm\times V_2}{348K}\\\\V_2=\frac{1.20\times 795\times 348}{0.55\times 389}=1.6\times 10^3mL$

Hence, the volume when the pressure and temperature has changed is $1.6\times 10^2mL$

5 0

3 years ago

A urine sample has a mass of 147 g and a density of 1.020 g/mL. What is the volume of this sample?

son4ous [18]

So we know that the equation for density is:

$D=\frac{m}{V}$

where D is the density, m is the mass in grams, and V is the volume in mL.

So since we know two of the variables, mass and density, we can solve for the volume:

$\frac{1.020g}{mL}=\frac{147g}{V}$

$V=\frac{147g}{\frac{1.020g}{mL}}$

$V=144.12mL$

Therefore, the volume of this urine sample is 144.12mL.

5 0

3 years ago