Answer:
Resistance can increase relative to Temperature, Nature of Material, Length of Conductor or wire.,and Cross-section area.
Explanation:
The pH of the buffer solution is 7.30 for 0.172 m in Hypochlorous acid and 0.131 m in Sodium hypochlorite.
<h3>What is a buffer solution?</h3>
A weak acid and its conjugate base, or a weak base and its conjugate acid, are mixed together to form a solution called a buffer solution, which is based on water as the solvent. They do not change in pH when diluted or when modest amounts of acid or alkali are added to them. A relatively little amount of a strong acid or strong base has little effect on the pH of buffer solutions. As a result, they are employed to maintain a steady pH.
According to the question:
Ka = 3.8×10⁻⁸
pKa = - log (Ka)
= - log(3.8×10⁻⁸)
= 7.42
pH = pKa + log {[conjugate base]/[acid]}
= 7.42+ log {0.131/0.172}
= 7.302
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Answer:
The remaining light bulbs will go out.
Explanation:
The light bulb that was taken out routed power to the other light bulbs, there for, not giving power to the next light bulbs will make them turn off or, "go out". This may be incorrect, as you did not provide a picture of the circuit.
-- The first thing I do when I wake up is go STRAIGHT to the bathroom. Up to that time, my displacement is equal to distance I traveled from my bed.
-- Once I'm relaxed and back in my room, dithering around and getting dressed, the distance I've traveled since I woke up is growing and growing, but my displacement is staying pretty steady, because I'm still hanging right around my bed.
-- I walk to school, walk between classes, maybe run around the track a couple times, walk to the lunchroom and back to classes, then walk home. By dinner time, my distance traveled during the day might be 3 or 4 MILES, but my displacement is only one floor down from my bedroom to the kitchen.
-- After my homework is done, I slide back into my warm bed and turn out the light. My displacement for the day is now zero ! The straight-line distance from the place I started to the place I finished is zero.
Power is the rate work done given by dividing work done by unit time. It is measured in watts equivalent to J/s.
In this case the force by the student is mg = 490 N (taking g as 9.8m/s²)
Work done is given by force × distance,
Therefore, Power =(force × distance)/ time, but velocity/speed =distance/time
Thus, Power = force × speed/velocity
= 490 N × 1.25
= 612.5 J/S (Watts)
Hence, power will be 612.5 Watts.