Answer:
104.5 and 109.5
Explanation:
Bond angle is the angle formed between three atoms which has at least two bonds present between them. The number of lone pairs in a covalent bond is a determinant of the bond angle as the lone pairs which are negatively charged repulses the bond pairs thereby creating a distortion and angle.
Studies have however shown that the bond angles in H3O are lesser than 109.5 and greater than 103.5. This provides a bond range of H3O.
<u>Answer:</u>
<em>The option which is true to the knowledge is second option.
</em>
<u>Explanation:</u>
The second option tells us that the attraction between the molecules is weak and movement of particles is less. Hence it makes the state x to be liquid because in case of liquid above the given fact is true to the knowledge.
While the other options are contradicting in nature for example if it is a solid that reaction will be strong and the movement will be very weak. And in case of gas that reaction will be very weak and movement will be very strong.
Answer: 1.52 atm
Explanation:
Given that:
Volume of gas V = 10.0L
Temperature T = 35.0°C
Convert Celsius to Kelvin
(35.0°C + 273 = 308K)
Pressure P = ?
Number of moles = 0.6 moles
Molar gas constant R is a constant with a value of 0.0821 atm L K-1 mol-1
Then, apply ideal gas equation
pV = nRT
p x 10.0L = 0.6 moles x (0.0821 atm L K-1 mol-1 x 308K)
p x 10.0L = 15.17 atm L
p = 15.17 atm L / 10.0L
p = 1.517 atm (round to the nearest hundredth as 1.52 atm)
Answer:
D. it decreases from top to bottom
Explanation:
Hey there!
The number of vacancies per unit volume => ( Nv = 2.3*10²⁵ m⁻³ )
Avogrado's number => ( NA = 6.022*10²³ atoms/mol )
Density of material ( p ) in g/m³ :
1 g/cm³ = 1000000 g/m³ so:
7.40 * ( 1000000 ) = 7.40*10⁶ g/m³
Atomic mass = 85.5 g/mol
* Calculate the number of atomic sites per unit volume :
N = NA * p / A
N = ( 6.022*10²³ ) * ( 7.40*10⁶ ) / 85.5
N = 4.45*10³⁰ / 85.5
N = 5.212*10²⁸ atoms/m³
Therefore:
Calculate the fraction of vacancies :
Fv = Nv / N
Fv = 2.3*10²⁵ / 5.212*10²⁸
FV = 4.441*10⁻⁴
Hope that helps!