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3 years ago

The two factors that affect the magnitude of the force are

Chemistry

1 answer:

viva [34]3 years ago

4 0

The strength of the gravitational force between two objects depends on two factors, mass and distance.

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Correct answer gets brainliest

sweet-ann [11.9K]

Answer:

e,b and d

Explanation:

5 0

3 years ago

Read 2 more answers

At 298 K the standard enthalpy of combustion of sucrose is -5645 kJ/mol and the standard reaction Gibbs energy is -5798 kJ/mol.

natka813 [3]

Explanation:

The given data is as follows.

T = 298 K, $\Delta H^{o}$ = -5645 kJ/mol

$\Delta G^{o}$ = -5798 kJ/mol

Relation between $\Delta H$ and $\Delta G$ are as follows.

$\Delta G^{o}$ = $\Delta H^{o} - T \Delta S^{o}$

-5798 kJ/mol = -5645 kJ/mol - $298 \times \Delta S^{o}$

-153 kJ/mol = - $298 \times \Delta S^{o}$

$\Delta S^{o}$ = 0.513 kJ/mol K

Now, temperature is $37^{o}C$ = (37 + 273) K = 310 K

Since, $\Delta G$ = $\Delta H^{o} - T \Delta S^{o}$

= $-5645 kJ/mol - 310 K \times 0.513 kJ/mol K$

= (-5645 kJ/mol - 159.03 kJ/mol)

= -5804.03 kJ/mol

As, change in Gibb's free energy = maximum non-expansion work

$\Delta G = \Delta G_{310 K} - \Delta G_{298 K}$

= -5804.03 kJ/mol - (-5798 kJ/mol)

= -6.03 kJ/mol

Therefore, we can conclude that the additional non-expansion work is -6.03 kJ/mol.

5 0

3 years ago

2. The table shows the scientific names and the common names of four plants. Which word in their names shows that two of the pla

posledela

Explanation:

the table is not given plz send the table

4 0

3 years ago

Fluorine-18 is a radioactive isotope that decays by positron emission to form oxygen-18 with a half-life of 109.8 min. (A positr

Lera25 [3.4K]

Answer:

k = 6.31 x 10⁻³ min⁻¹

Explanation:

The equation required to solve this question is:

k = 0693 / t half-life

This equation is derived from the the equation from the radioctive first order reactions:

ln At/A₀ = -kt

where At is the number of isoopes after a time t , and A₀ is the number of of isotopes initially. The half-life is when the number of isotopes has decayed by a half, so

ln(1/2) = -kt half-life

-0.693 = - k t half-life

t half-life = 109.8 min

⇒ k = 0.693 / t half-life = 0.693 / 109.8 min = 6.31 x 10⁻³ min⁻¹

6 0

3 years ago

Consider a transition of the electron in the hydrogen atom from n=3 to n=7.

kow [346]

Answer:

For a: The wavelength of light is $1.005\times 10^{-6}m$

For b: The light is getting absorbed

Explanation:

For a:

To calculate the wavelength of light, we use Rydberg's Equation:

$\frac{1}{\lambda}=R_H\left(\frac{1}{n_i^2}-\frac{1}{n_f^2} \right )$

Where,

$\lambda$ = Wavelength of radiation

$R_H$ = Rydberg's Constant = $1.097\times 10^7m^{-1}$

$n_f$ = Higher energy level = 7

$n_i$ = Lower energy level = 3

Putting the values in above equation, we get:

$\frac{1}{\lambda }=1.097\times 10^7m^{-1}\left(\frac{1}{3^2}-\frac{1}{7^2} \right )\\\\\lambda =1.005\times 10^{-6}m$

Hence, the wavelength of light is $1.005\times 10^{-6}m$

For b:

There are two ways in which electrons can transition between energy levels:

Absorption spectra: This type of spectra is seen when an electron jumps from lower energy level to higher energy level. In this process, energy is absorbed.
Emission spectra: This type of spectra is seen when an electron jumps from higher energy level to lower energy level. In this process, energy is released in the form of photons.

As, the electron jumps from lower energy level to higher energy level. The wavelength is getting absorbed.

6 0

4 years ago