Volume of Hydrogen V1 = 351mL
Temperature T1 = 20 = 20 + 273 = 293 K
Temperature T2 = 38 = 38 + 273 = 311 K
We have V1 x T2 = V2 x T1
So V2 = (V1 x T2) / T1 = (351 x 311) / 293 = 372.56
Volume at 38 C = 373 ml
Answer:
Photosynthesis
Explanation:
Photosynthesis uses energy from light to convert water and carbon dioxide molecules into glucose (sugar molecule) and oxygen. The oxygen is released, or “exhaled”, from leaves while the energy contained within glucose molecules is used throughout the plant for growth, flower formation, and fruit development.
Answer: B
Explanation:
According to Ohm's Law, the answer is B.
Ohm's Law states that power is equal to volume x current.
If volume x current equals power, that means they are both 50% of power.
Ohm's Law:
power = voltage x current
current = voltage x power
voltage = power x current
I hope this answer helped.
<u>Answer:</u> The solubility of carbon dioxide at 5.50 atm is 
<u>Explanation:</u>
To calculate the molar solubility, we use the equation given by Henry's law, which is:

Or,

where,
are the initial concentration and partial pressure of carbon dioxide
are the final concentration and partial pressure of carbon dioxide
We are given:

Putting values in above equation, we get:

Hence, the solubility of carbon dioxide at 5.50 atm is 