Unlike velocity, speed is scalar, which means it is described by only

A 10N force and a 50N force act in opposite directions on a 4 kg object. What is the acceleration? ( how did you do it )

Anastaziya [24]

To find the acceleration, we will use the formula

F=ma

Here the net force will be 40N (50 - 10)

F = ma

40 = 4a

40/4 = a

10 m/s^2 = a

Hope you understood !

3 0

4 years ago

A Cat is on a balcony floor (90cm below the railing), keenly eyeing a butterfly hovering 60 cm above the railing. With what spee

GenaCL600 [577]

We will have the following:

First, the equation to use is the following:

$d=v_ot+\frac{1}{2}at^2$

Now, we transform the total distance the cat would need to travel:

$90\operatorname{cm}+60\operatorname{cm}=150\operatorname{cm}\cdot\frac{1m}{100\operatorname{cm}}=1.5m$

So, the cat would need to travel 1.5 meters. ("d" in the equation).

Now, using the speed given we determine the time it would take the cat to traverse the 1.5 meters:

$t=\frac{1.5m\cdot1s}{0.45m}\Rightarrow t=\frac{10}{3}\Rightarrow t=3.333\ldots$

So, the time it would take the cat to traverse the distance will be approximately 3.33 seconds.

Now, we know that the acceleration will be given by Earth's gravity, so:

$1.5m=v_0(\frac{10}{3}s)+\frac{1}{2}(-\frac{9.8m}{s^2})(\frac{10}{3}s)^2\Rightarrow1.5m=v_0(\frac{10}{3}s)+(-\frac{490}{9}m)$ $\Rightarrow\frac{1007}{18}m=v_0(\frac{10}{3}s)\Rightarrow v_0=\frac{1007}{60}\frac{m}{s}\Rightarrow v_0=16.78333\ldots$

So, the initial vvelocity the cat must leave the floor in order to arrive at the butterfly with the optimum pouncing speed of 0.45 m/s is approximately 16.78 m/s or exactly 1007/60 m/s.

5 0

2 years ago

Kinetic energy is the energy of . It increases with and .Potential energy is the energy of or . It increases with , and

lorasvet [3.4K]

Answer:

k is the energy of motion it increase with four of load you carry

8 0

3 years ago

☆ Correct and rewrite the following statements:

il63 [147K]

Answer:

<h3>a) </h3><h3>Question:-</h3>

Rubber is a good conductor of electricity.

<h3>Answer:-</h3>

It's incorrect sentence.
As we know that, rubber are an insulators of electricity, and they do not not have free ions which can help in conducting electricity.

So correct sentence is:

Rubber is a bad conductor of electricity.

<h3>b)</h3><h3>Question:-</h3>

Electroplating wastes are useful to human health and environment.

<h3>Answer:-</h3>

It's incorrect sentence. 
As we know that, electroplating of substances releases harmful and toxic substances into the environment causing serious health issues in human, so it's waste substances released into environment can have very harmful effects.

So correct sentence is:

Electroplating wastes are harmful to human health and environment.

<h3>c)</h3><h3>Question:-</h3>

In an LED bulb, the shorter lead is connected to the positive terminal of the battery.

<h3>Answer:-</h3>

It's incorrect sentence. 
As we know that, in an LED bulb their are two terminals that is the positive and the negative. So here the lead connected to the positive terminal is always slightly longer than the lead connected to negative terminal of the bulb.

So correct sentence is:

In an LED bulb, the longer lead is connected to the positive terminal of the battery.

<h3>d)</h3><h3>Question:-</h3>

Pure water conducts electricity.

<h3>Answer:-</h3>

It's incorrect sentence. 
As we know that, pure water is a form of H2O where Hydrogen (H) is positive ion and Oxygen (O) is a negative ion which can conduct electricity when they are in individuals but as in pure water they are in combined form of compound H2O in which they become neutral and can't conduct any electricity.

So correct sentence is:

Pure water can't conduct electricity.

3 0

2 years ago

Derive a general formula for projectile motion with the object launched at an angle

vagabundo [1.1K]

Answer:

y = x tan θ - (g / 2v₀² cos² θ) x²

Explanation:

An equation is called a general formula that relates the position on the x-axis and the height on the body's axis.

Let's write the position on each axis

X axis. No acceleration

x = v₀ₓ t

Y Axis. There is the acceleration of gravity

y = $v_{oy}$ t - ½ g t²

Let's clear the time in the first equation and substitute in the second

y = v₀ sin θ (x / v₀ₓ) - ½ g (x / v₀ₓ)²

y = v₀ sin θ / v₀ cos θ x - ½ g x² / v₀² cos² θ

y = x tan θ - (g / 2v₀² cos² θ) x²

This is the trajectory equation in projectile launching

6 0

3 years ago