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Tasya [4]
3 years ago
7

A(n) 1700 kg car is moving along a level road at 21 m/s. The driver accelerates, and in the next 10 s the engine provides 22000

J of additional energy. If 3666.67 J of this energy must be used to overcome friction, what is the final speed of the car
Physics
1 answer:
allochka39001 [22]3 years ago
4 0

The final speed of the car at the given conditions is 30.1 m/s.

The given parameters:

  • <em>Mass of the car, m = 1700 kg</em>
  • <em>Velocity of the car, v = 21 m/s</em>
  • <em>Time of motion, t = 10 s</em>
  • <em>Additional energy provided by the engine, E₁ = 22,000 J</em>
  • <em>Energy used in overcoming friction, E₂ = 3,666.67 J</em>

The change in the energy applied to the car is calculated as;

\Delta E = E_1 - E_2\\\\\Delta E = 22,000 \ J \ - \ 3,666.67 \ J\\\\\Delta  E = 18,333.33 \ J

The final speed of the car is calculated as follows;

\Delta E = \frac{1}{2} m(v_f^2 - v_0^2)\\\\v_f^2 - v_0^2 = \frac{2\Delta E}{m} \\\\v_f^2  = \frac{2\Delta E}{m} + v_0^2\\\\v_f = \sqrt{ \frac{2\Delta E}{m} + v_0^2} \\\\v_f = \sqrt{ \frac{2\times 18,333.4}{1700} + (21)^2} \\\\v_f = 30.1 \ m/s

Thus, the final speed of the car at the given conditions is 30.1 m/s.

Learn more about change in kinetic energy here: brainly.com/question/6480366

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Step by step Solution

The work done by a force is defined as the product of the force and the distance traveled in the direction of motion.

The first answer "Only the component of the force perpendicular to the motion is used to calculate the work" is wrong because, the force perpendicular to motion does no work.

The second choice "If the force acts in the same direction as the motion, then no work is done" is wrong because the work in the direction of the force is W=F\times d.

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