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ycow [4]
3 years ago
15

A negative test charge will accelerate toward regions of ________ electric potential and ________ electric potential energy.

Physics
1 answer:
dalvyx [7]3 years ago
5 0

Answer: higher and lower

Explanation:

 charge in an electric field will experience a force in the direction of decreasing potential energy. Since the electric potential energy of a negative charge is equal to the charge times the electric potential the direction of decreasing electric potential energy is the direction of increasing electric potential.

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Calculate the ratio of the kinetic energy of an electron to that of a proton if their wavelengths are equal. Assume that the spe
goblinko [34]

Answer:

the ratio of the kinetic energy of an electron to that of a proton if their wavelengths are equal is 1835.16 .

Explanation:

We know, wavelength is expressed in terms of Kinetic Energy by :

\lambda=\dfrac{h}{\sqrt{2mE}}

Therefore , E=\dfrac{h^2}{2 \lambda^2 m}

It is given that both electron and proton have same wavelength.

Therefore,

E_e=\dfrac{h^2}{2 \lambda^2 m_e}   .... equation 1.

E_p=\dfrac{h^2}{2 \lambda^2 m_p}   .... equation 2.

Now, dividing equation 1 by 2 .

We get ,

\dfrac{E_e}{E_p}=\dfrac{\dfrac{h^2}{2 \lambda^2 m_e}}{\dfrac{h^2}{2 \lambda^2 m_p}}\\\\\\\dfrac{E_e}{E_p}=\dfrac{m_p}{m_e}

Putting value of mass of electron = 9.1\times 10^{-31}\ kg and mass of proton = 1.67\times 10^{-27}\ kg.

We get :

\dfrac{E_e}{E_p}=\dfrac{1.67\times 10^{-27}\ kg}{9.1\times 10^{-31}\ kg}=1835.16

Hence , this is the required solution.

4 0
4 years ago
Read 2 more answers
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