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GuDViN [60]
2 years ago
15

PLEASE HELP I DON´T KNOW WHAT THE DIFFERENCE BETTWEEN THE TWO IS!

Chemistry
1 answer:
SSSSS [86.1K]2 years ago
5 0

Answer:

A reactant is a substance that is present at the start of a chemical reaction. A product is a substance that is present at the end of a chemical reaction.

Explanation:

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3k+aici3 3kci+ai is what type of reaction
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3K      +     AlCl3 -------->  3 KCl     +          Al
element    compound     compound       element

This is single replacement (displacement) reaction.
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3 years ago
which objects would have a greater gravitational force between them, Objects A and B, or Objects B and C? HELPPP
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Dude what are the objects!
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3 years ago
How is electronegativity related to covalent bonding?
Zolol [24]

Answer:

Atoms must have similar electronegativities in order to share electrons in a covalent bond.

Explanation:

Covalent bonding is one of the bondings that occurs between the atoms of elements. It is the bonding in which atoms share their valence electrons with one another. However, the ELECTRONEGATIVITY, which is the ability of an atom to be attracted to electrons play a major role in the formation of covalent bonds.

When atoms of different electronegativities combine, the more electronegative atom pulls more electrons towards itself, hence, an IONIC bond is formed. However, when the electronegativities of the atoms are similar, the sharing of their electrons becomes stronger. Hence, ATOMS MUST HAVE SIMILAR ELECTRONEGATIVITIES in order to share electrons in a covalent bond.

5 0
3 years ago
Read 2 more answers
What is the half-life of a pharmaceutical if the initial dose is 500 mg and only 31 mg remains after 6 hours?
Sergeu [11.5K]

Answer:

\large \boxed{\text{b. 1.5 h}}

Explanation:

1. Calculate the rate constant

The integrated rate law for first order decay is

\ln \left (\dfrac{A_{0}}{A_{t}}\right ) = kt

where

A₀ and A_t are the amounts at t = 0 and t

k is the rate constant

\begin{array}{rcl}\ln \left (\dfrac{500}{31}\right) & = & k \times 6\\\\\ln 16.1 & = & 6k\\2.78& =& 6k\\k & = & \dfrac{2.78}{6}\\\\& = & 0.463 \text{ h}^{-1}\\\end{array}

2. Calculate the half-life

t_{\frac{1}{2}} = \dfrac{\ln2}{k} = \dfrac{\ln2}{\text{0.463  h}^{-1}} = \textbf{1.5 h}\\\\ \text{The half-life is $\large \boxed{\textbf{1.5 h}}$}

4 0
3 years ago
1. Which of the following is an SI base unit for time? (2 points)
oee [108]
Number one would be Decades
6 0
3 years ago
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