To solve this problem it is necessary to apply the concepts given in the kinematic equations of movement description.
From the perspective of angular movement, we find the relationship with the tangential movement of velocity through
Where,
Angular velocity
v = Lineal Velocity
R = Radius
At the same time we know that the acceleration is given as the change of speed in a fraction of the time, that is
Where
Angular acceleration
Angular velocity
t = Time
Our values are
Replacing at the previous equation we have that the angular velocity is
Therefore the angular speed of a point on the outer edge of the tires is 66.67rad/s
At the same time the angular acceleration would be
Therefore the angular acceleration of a point on the outer edge of the tires is 
.98 Newton’s because you convert 100 g to kg which is .1 kg them you multiply.1 kg by 9.8 and get .98 and the units of the force are in Newton’s
The length of the inclined plane is approximately 12 ft
The situation forms a right angle triangle.
<h3>Right triangle</h3>
Right triangle have one of its angle as 90 degrees.
Therefore,
The length of the inclined plane is the hypotenuse of the triangle. The length of the inclined plane can be found using trigonometric ratios.
height = 4 ft
angle(∅) = 19.45°
sin 19.45 = 4 / h
h = 4 / 0.33298412235
h = 12.0125847796
h = 12 ft
Therefore, the length of the inclined plane is approximately 12 ft
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