Explanation:
It is given that initially pressure of ideal gas is 4.00 atm and its temperature is 350 K. Let us assume that the final pressure is and final temperature is .
(a) We know that for a monoatomic gas, value of is \frac{5}{3}[/tex].
And, in case of adiabatic process,
= constant
also, PV = nRT
So, here = 350 K, , and
Hence,
= 267 K
Also, = 4.0 atm, , and
= 2.04 atm
Hence, for monoatomic gas final pressure is 2.04 atm and final temperature is 267 K.
(b) For diatomic gas, value of is \frac{7}{5}[/tex].
As, = constant
also, PV = nRT
= 350 K, , and
= 289 K
And, = 4.0 atm, , and
= 2.27 atm
Hence, for diatomic gas final pressure is 2.27 atm and final temperature is 289 K.
Answer:
Natural Selection, Hope this helps
Explanation:
Answer:
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Answer:
It's may help you to answer
Answer:
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