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GaryK [48]
3 years ago
14

Technician A says that one heater hose should be hot and the other hose cool if the heater is functioning okay. Technician B say

s that both hoses should be hot to the touch. Which technician is correct?A) Technician A onlyB) Technician B onlyC) Both techniciansD) Neither technician
Physics
1 answer:
Alika [10]3 years ago
4 0

Answer:

The correct answer to the question is

B) Technician B only

Explanation:

A heater hose is a relatively inexpensive rubber hose used to transmit engine coolant though the engine to the radiator that supplies the heat required in the cabin. They normally extend from the engine to the dash board.

The heater hoses should be hot. If the hoses are cold, it is an indication of a blocked flow from either the heater control valves is blocked   or the radiator becoming clocked with debris.

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What determines how the different moon phases appear from earth
pychu [463]

Answer:

The position of the earth and moon.

Explanation:

The position of the earth and moon are the two main factors.

Hope this helps, have great day/night!

7 0
3 years ago
Read 2 more answers
A force of 1.150×103 N pushes a man on a bicycle forward. Air resistance pushes against him with a force of 795 N. If he starts
nalin [4]

Answer:

He has a speed of 16.60m/s after 35.0 meters.

Explanation:

The final velocity can be determined by means of the equations for a Uniformly Accelerated Rectilinear Motion:

v_{f}^{2} = v_{i}^{2} + 2ad        

v_{f} = \sqrt{v_{i}^{2} + 2ad}  (1)

The acceleration can be found by means of Newton's second law:

\sum F_{net} = ma

Where \sum F_{net} is the net force, m is the mass and a is the acceleration.

Fx + Fy = ma  (2)

All the forces can be easily represented in a free body diagram, as it is shown below.

Forces in the x axis:

F_{x} = F - F_{air}  (3)

Forces in the y axis:

F_{y} = 0 (4)

Solving for the forces in the x axis:

F_{x} = F - F_{air}

Where F = 1.150x10^{3} N and F_{air} = 795 N:

F_{x} = 1.150x10^{3} N - 795 N

F_{x} = 355 N

Replacing in equation (2) it is gotten:

Fx + Fy = ma

355 N + 0 N = (90.0 Kg)a

355 N = (90.0 Kg)a

a = \frac{355 N}{90.0Kg}

a = \frac{355 Kg.m/s^{2}}{90.0Kg}

a = 3.94 m/s^{2}

So the acceleration for the cyclist is 3.94 m/s^{2}, now that the acceleration is known, equation (1) can be used:

v_{f} = \sqrt{v_{i}^{2} + 2ad}

However, since he was originally at rest its initial velocity will be zero (v_{i} = 0).

v_{f} = \sqrt{2ad}

v_{f} = \sqrt{2(3.94m/s^{2})(35.0m)}

v_{f} = 16.60m/s

He has a speed of 16.60m/s after 35.0 meters

8 0
3 years ago
If you know what a JW is LET ME KNOW and it is a type of ppl
lisabon 2012 [21]

Answer:

only thing I think of when I see that is 'Just Wondering'

Explanation:

3 0
3 years ago
Read 2 more answers
An inflatable raft (unoccupied) floats down a river at an approximately constant speed of 5.6 m/s. A child on a bridge, 71 m abo
saveliy_v [14]

Answer:

21.28 m

Explanation:

height, h = 71 m

velocity of raft, v = 5.6 m/s

let the time taken by the stone to reach to raft is t.

use second equation of motion for stone

h = ut + \frac{1}{2}at^{2}

u = 0 m/s, h = 71 m, g = 9.8 m/s^2

71 = 0 + 0.5 x 9.8 x t^2

t = 3.8 s

Horizontal distance traveled by the raft in time t

d = v x t = 5.6 x 3.8 = 21.28 m

3 0
3 years ago
A student, Daniela, is arguing that since a meteor is weightiess in space, if it crashes
zmey [24]

Answer:

she's wrong because she is and there it doesn't say she's right

5 0
2 years ago
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