Answer:
Explanation:
Force between two charges is given by the following expression
F = 
Q₁ and Q₂ are two charges and d is distance between two.
.1 =
If Q₁ becomes three times , force will become 3 times . Hence force becomes .3 N in the first case.
Force F = .3 N
If charge becomes one fourth , force also becomes one fourth .
F= 
= .025 N.
Weight because both gravity and weight are pulling an object down
The force that peter applies to the object of distance 40m is 75N.
<h3>HOW TO CALCULATE FORCE</h3>
The force applied to an object can be calculated by dividing the work done on the object by the distance moved. That is;
Force = Work done ÷ distance
According to this question, the work done is 3000 joules while the distance moved is 40m. The force is calculated as follows:
Force = 3000J ÷ 40m
Force = 75N
Therefore, the force that peter applies to the object of distance 40m is 75N.
Learn more about force at: brainly.com/question/26115859
Answer:
3.528×10² V.
Explanation:
potential difference: This is the work done when one coulomb of charge moves from one point to another in an electric field. The S.I unit of potential difference is volt. The formula of potential difference is given as,
V = kq/r..................... Equation 1
And
E = kq/r² .................. Equation 2
Comparing equation 1 and equation 2,
V = E×r............................. Equation 3
Where V = potential difference, E = Electric field between the plate of the capacitor, r = distance between the plate.
Given: E = 6.3×10⁵ V/m, r = 0.56 mm = 0.00056 m.
Substitute into equation 3,
V = 6.3×10⁵×0.00056
V = 3.528×10² V.
Hence the potential difference of the plate = 3.528×10² V.
According to the Law of Conservation of Charge, the net
charge remains constant. If both things have different charges, upon contact,
they would share the charge equally. In this case, the total charge is -16μC.
The final charge for each ball would be -8 μC.
