Given:
Moles of H2 = 0.300
Moles of I2 = 0.400
Moles of HI = 0.200
Keq = 870
To determine:
Amounts of the mixture at equilibrium
Explanation:
H2(g) + I2(g) ↔ 2HI(g)
Initial 0.3 0.4 0.2
Change -x -x +2x
Eq (0.3-x) (0.4-x) (0.2+2x)
Keq = [HI]²/[H2][I2]
870 = (0.2+2x)²/(0.3-x)(0.4-x)
x = 0.29 moles
Amounts at equilibrium:
[HI] = 0.2 + 2(0.29) = 0.78 moles
[H2] = 0.3-0.29 = 0.01 moles
[I2] = 0.4-0.29 = 0.11 moles
Explanation:
oxidation is adding of oxygen and removal of hydrogen.
Reduction means removal of oxygen and addition of hydrogenm
Hello!
CH3(CH2)4CCH
or <span> C7H12
</span>
<span>hydrocarbon: </span>
1-heptyne
Answer:
C.
Explanation: In nuclear fission and fusion reactions, some of the energy in matter is converted to energy. If you weigh the reactants and the products, the products will weigh less than the reactants. This is called the mass defect and is the result of turning matter into energy.
Answer:
Lithium and Chlorine and oxygen and Bromine are likely to form ionic compound.
Explanation:
Ionic compounds allows one or more electrons to be transferred from metals to non metals
Lithium and Chlorine will form Lithium Chloride (LiCL)
Oxygen and Bromine will form Bromine dioxide, because of two electrons from oxygen are transferred.