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Furkat [3]
3 years ago
10

An electric field of 260 000 n/c points due west at a certain spot. what are the magnitude and direction of the force that acts

on a charge of #7.0 !c at this spot
Physics
1 answer:
GrogVix [38]3 years ago
3 0

the force on the charge is 1820000 N and is directed along the west.

Explanation:

Force = F =q E

q= charge= 7 C

E= electric field=260000 N/C

so F=7 (260000)

F=1820000 N

The force acting on the charge is along west.

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Say I have a series circuit with 20v and four 65 ohm resistors, what is the current in each resistor?
Komok [63]
Data:

E = 20 V
R_{1} = 65\Omega
R_{2} = 65\Omega
R_{3} = 65\Omega
R_{4} = 65\Omega

<span>Now that we have all the values ​​we need properly identified, simply calculate the equivalent total resistance of the circuit and the intensity of the total electric current using the Ohm's Law:

</span>R_{T} =  R_{1} + R_{2} + R_{3} + R_{4}
R_{T} = 65 + 65 + 65+ 65
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<span>Like this:
</span>
I_{T} =  \frac{E}{ R_{T} }

I_{T} = \frac{20}{ 260 }
I_{T} = 0,076923076...

\boxed{\boxed{I_{T} \approx 0,07A}} 
Answer:
<span>The intensity of the total electric current 
</span>\boxed{\boxed{I_{T} \approx 0,07A}} 

P.S:. Since the association is in series, the current of 0.07A is the same for all resistors.
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Answer:

Explanation:

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