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Furkat [3]
3 years ago
10

An electric field of 260 000 n/c points due west at a certain spot. what are the magnitude and direction of the force that acts

on a charge of #7.0 !c at this spot
Physics
1 answer:
GrogVix [38]3 years ago
3 0

the force on the charge is 1820000 N and is directed along the west.

Explanation:

Force = F =q E

q= charge= 7 C

E= electric field=260000 N/C

so F=7 (260000)

F=1820000 N

The force acting on the charge is along west.

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During the removal of wastes in a cell, the waste products move
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DedPeter [7]

Most fish fossils are: <u>D. from sharks, eels, and stingrays</u>.

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8 0
4 years ago
A missile is launched upward with a speed that is half the escape speed. What height (in radii of Earth) will it reach?
timofeeve [1]

Answer:

The height (h) will be: \frac{3}{4}R =h  

Explanation:

The scape speed equation is given by:

v_{scape}=\sqrt{\frac{2GM}{R}}

Now, the speed of the missile is

v_{missile}=\frac{1}{2}v_{scape}

v_{scape}=\frac{1}{2}\sqrt{\frac{2GM}{R}}

Using the conservation of energy, we can find the maximu height of the missile.

E_{i}=E_{f}

\frac{1}{2}mv_{scape}^{2}-mgR =-mgh

\frac{1}{2}\frac{2GM}{4R}-gR =-gh

\frac{GM}{4R}-gR =gh

Let's recall that g = GM/R², using the equivalence principle. When R is the radius of the earth and M is the mass of the earth.

\frac{1}{4}gR-gR =-gh

\frac{1}{4}R-R =-h    

Therefore the height (h) will be:

\frac{3}{4}R =h    

I hope it helps you!

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