Answer:
The solution is attached in the pictures below
Explanation:
Answer:
Explanation:
We shall first calculate the velocity at height h = 575 m .
acceleration a = 2.2 m /s²
v² = u² + 2 a s
u is initial velocity , v is final velocity , s is height achieved
v² = 0 + 2 x 2.2 x 575
v = 50.3 m /s
After 575 m , rocket moves under free fall so g will act on it downwards
If it travels further by height H
from the relation
v² = u² - 2 g H
v = 0 , u = 50.3 m /s
H = ?
0 = 50.3² - 2 x 9.8 H
H = 129.08 m
Total height attained by rocket
= 575 + 129.08
= 704.08 m .
Answer:60 gm
Explanation:
Given
initial velocity of ball 
Force exerted by racquet 
time period of force 
final velocity of ball 
Racquet imparts an impulse to the ball which is given by



Answer: I would say it would be 3.9
but i believe there is something missing shorty.
Answer:
The speed of waves on this wire is 329.14 m/s
Explanation:
Given;
tension of the wire, T = 650 N
mass per unit length, μ = 0.06 g /cm = 0.006 kg/m
(convert the unit of mass per length in g/cm to kg/m by dividing by 10 = 0.06 / 10 = 0.006 kg/m)
The speed of waves on this wire is given as;
Therefore, the speed of waves on this wire is 329.14 m/s