All categories

2 years ago

Help plsss I need to answer this

Physics

2 answers:

Reil [10]2 years ago

8 0

Might be a bit i don’t know

Natali [406]2 years ago

6 0

Answer:

180 volts

Explanation:

You might be interested in

A person's center of mass is easily found by having the person lie on a reaction board. A horizontal, 2.1-m-long, 6.6 kg reactio

MrRissso [65]

Answer is x hopefully this helps your stupid head

5 0

3 years ago

A capacitor consists of two parallel plates, each with an area of 17.0 cm2 , separated by a distance of 0.150 cm . The material

Llana [10]

Answer:

a) $C = 40.138\,pF$ , b) $q = 16.056\,nC$ , c) $U = 3.212\,\mu J$

Explanation:

a) The capacitance of two parallel plates capacitor with dielectric is given by the following expression:

$C = K\cdot \epsilon_{o}\cdot \frac{A}{d}$

Where:

$K$ - Dielectric constant.

$\epsilon_{o}$ - Vaccum permitivity.

$A$ - Plate area.

$d$ - Distance between plates.

Hence, the capacitance of the system is:

$C = (4.00)\cdot (8.854\times 10^{-12}\,\frac{F}{m} )\cdot \left(\frac{17\times 10^{-4}\,m^{2}}{0.150\times 10^{-2}\,m}\right)$

$C = 4.014\cdot 10^{-11}\,F$

$C = 40.138\,pF$

b) The charge can be found by using the definition of capacitance:

$q = C\cdot V_{batt}$

$q = (4.014\times 10^{-11}\,F)\cdot (400\,V)$

$q = 1.606\times 10^{-8}\,C$

$q = 16.056\,nC$

c) The energy stored in the charged capacitor is:

$U=\frac{1}{2}\cdot Q\cdot V_{batt}$

$U=\frac{1}{2}\cdot (1.606\times 10^{-8}\,C)\cdot (400\,V)$

$U = 3.212\times 10^{-6}\,J$

$U = 3.212\,\mu J$

3 0

2 years ago

Read 2 more answers

Make I the subject<br> E=VIt

slava [35]

To Make I the subject you need to get it by itself. To do this divide both sides by V and t:

I = E/Vt

5 0

3 years ago

Question 1 of 20

jolli1 [7]

Answer:

Explanation:

5 0

2 years ago

Read 2 more answers

A sample of a diatomic ideal gas has pressure P and volume V. When the gas is warmed, its pressure triples and its volume double

Andreyy89

Answer:

Amount of Energy transferred $=8.5PV$

Explanation:

Given:

Initial volume=V

Initial pressure=P

Final volume=2V

Final pressure=3P

Now w know that the Energy transferred in constant pressure pressure is given by

$E_1=nc_pdT\\\\E_1=n\times\dfrac{7R}{2}dT\\E_1=3.5(nRdT)\\E_1=3.5(V(2P-P))\\E_1=3.5PV$

Now the Energy transferred in constant volume process is given by

$E_2=nc_vdT\\\\E_2=n\times\dfrac{5R}{2}dT\\E_1=2.5(nRdT)\\E_1=2.5(V(3V-V))\\E_1=5PV$

The total Energy transferred is given by

$E_{total}=E_1+E_2\\E{total}=3.5PV+5PV\\=8.5PV$

3 0

3 years ago

Read 2 more answers

Help plsss I need to answer this​

Help plsss I need to answer this