Answer:
117.8 m/s
Explanation:
Given that:
String length, L = 0.28
pipe length, L' = 0.82
Speed of sound in air, v = 345 m/s
n = 3 (3rd harmonic)
Frequency, f of 3rd harmonic ;
f = (v*n) / 2L - - - - (1)
for the pipe: ; 3rd harmonic
f = (v*n) / 2L' - - - (2)
Equating (1) and (2)
(v*n) / 2L = (v*n) / 2L'
2L' * v * n = v* n * 2L
v = vL / L'
v = (345 * 0.28) / 0.82
v = 96.6 / 0.82
v = 117.80487
v = 117.8 m/s
Answer:
= 0.517 m
Explanation:
This is a resonance exercise where the ends of the string are fixed, therefore it has a node of them, the fundamental (longest) wavelength created has the form
λ = 2L
wave speed is related to wavelength and frequency
v = λ f
v = 2L f
let's calculate
v = 2 0.50 440
v = 440 m / s
since they indicate that the tension of the string does not change and the linear density of the string is constant, the speed of the wave also remains constant
f =
let's find the length for the new resonance frequency
L =
let's calculate
L =
L = 0.5166 m
Answer:
E) V=(m/M)v
Explanation:
Given that
Mass of the small ball = m
Initial velocity of the small ball = v
Mass of the larger ball = m
Initial velocity of the larger ball = 0
After the collision
The velocity of the small ball = 0
The velocity of the larger ball = V
There is no any external force that is why linear momentum will be conserve.
From linear momentum conservation
Pi=Pf
m v + M x 0 = m x 0 + M V
m v +0 = 0 + M V
Therefore the answer will be E.
E) V=(m/M)v
Answer:
21.67 m/s²
Explanation:
From the question given above, the following data were obtained:
Velocity (v) = 49.7 m/s
Radius (r) = 114 m
Centripetal acceleration (a) =?
The centripetal acceleration can be obtained by using the following formula:
a = v²/r
a = 49.7² / 114
a = 2470.09 / 114
a = 21.67 m/s²
Therefore, the centripetal acceleration of the car is 21.67 m/s²
The mineral with Mohs hardness would be scratched because the mineral with Mohs 7 hardness is stronger than the Mohs 5 mineral. Eventually, that mineral would turn into dust if you kept rubbing it.