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vlabodo [156]
3 years ago
14

Write a definition for the word epicenter

Physics
1 answer:
docker41 [41]3 years ago
3 0

Explanation: Epicenter is the part of the earth's surface directly above the focus of an earthquake.

I hope this helps you.

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The answer is 7.66. c:

6 0
3 years ago
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A 1300 kg steel beam is supported by two ropes. (Figure
Dmitriy789 [7]

Relative to the positive horizontal axis, rope 1 makes an angle of 90 + 20 = 110 degrees, while rope 2 makes an angle of 90 - 30 = 60 degrees.

By Newton's second law,

  • the net horizontal force acting on the beam is

R_1 \cos(110^\circ) + R_2 \cos(60^\circ) = 0

where R_1,R_2 are the magnitudes of the tensions in ropes 1 and 2, respectively;

  • the net vertical force acting on the beam is

R_1 \sin(110^\circ) + R_2 \sin(60^\circ) - mg = 0

where m=1300\,\rm kg and g=9.8\frac{\rm m}{\mathrm s^2}.

Eliminating R_2, we have

\sin(60^\circ) \bigg(R_1 \cos(110^\circ) + R_2 \cos(60^\circ)\bigg) - \cos(60^\circ) \bigg(R_1 \sin(110^\circ) + R_2 \sin(60^\circ)\bigg) = 0\sin(60^\circ) - mg\cos(60^\circ)

R_1 \bigg(\sin(60^\circ) \cos(110^\circ) - \cos(60^\circ) \sin(110^\circ)\bigg) = -\dfrac{mg}2

R_1 \sin(60^\circ - 110^\circ) = -\dfrac{mg}2

-R_1 \sin(50^\circ) = -\dfrac{mg}2

R_1 = \dfrac{mg}{2\sin(50^\circ)} \approx \boxed{8300\,\rm N}

Solve for R_2.

\dfrac{mg\cos(110^\circ)}{2\sin(50^\circ)} + R_2 \cos(60^\circ) = 0

\dfrac{R_2}2 = -mg\cot(110^\circ)

R_2 = -2mg\cot(110^\circ) \approx \boxed{9300\,\rm N}

8 0
2 years ago
Suggest a situation where we can obtain more than one shadow of an object at a time?
Murljashka [212]

Answer:

We can obtain more than one shadow of an object if light from more than one source falls on it. [For example during a match being played in a stadium multiple shadows of players are seen].

Explanation:

nah-

4 0
3 years ago
What is gravitational energy ?
Tanzania [10]
The energy of one massive object has in relation with another massive object due to gravity is called gravity
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What is the name for family labeled #4 (Yellow)?
goldfiish [28.3K]

Answer:

transition metals im sorry if this was too late

4 0
3 years ago
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