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3 years ago

Write a definition for the word epicenter

Physics

1 answer:

docker41 [41]3 years ago

3 0

Explanation: Epicenter is the part of the earth's surface directly above the focus of an earthquake.

I hope this helps you.

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Identify the type of force described (contact or noncontact):

Soloha48 [4]

Answer:

1.contact force

2. Non contact

Explanation:

1. Because bodies are in contact

2.Bodies are not in contact.

8 0

3 years ago

Read 2 more answers

An electron is projected with an initial speed of 5 3.2 10 / ⋅ m s directly toward a proton that is fixed in place. If the elect

Dvinal [7]

Answer:

The distance is $d =1.66*10^{-9}m$

Explanation:

From the question we are told that

The initial speed of the electron is $v_i = 3.2 *10^5 m/s$

The mass of electron is $m = 9.11*10^{-31}kg$

Let $d$ be the distance between the electron and the proton when the speed of the electron instantaneously equal to twice the initial value

Let $KE_i$ be the initial kinetic energy of the electron \

Let $KE_d$ be the kinetic energy of the electron at the distance $d$ from the proton

Considering that energy is conserved,

The energy at the initial position of the electron = The energy at the final position of the electron

i.e

$KE_i +U_1 = KE_d + U_2$

$U_1 \ and \ U_2$ are the potential energy at the initial position of the electron and at distance d of the electron to the proton

Here $U_1 = 0$

So the equation becomes

$\frac{1}{2} mv_i^2 = \frac{1}{2} mv_d^2 + \frac{kq_1 q_2}{d}$

Here $q_1 \ and \ q_2$ are the charge on the electron and the proton and their are the same since a charge on an electron is equal to charge on a proton

$k$ is electrostatic constant with value $8.99*10^9 N \cdot m^2 /C^2$

i.e $q = 1.602 *10^{-19}C$

$v_d$ is the velocity at distance d from the proton = 2 $v_i$

So the equation becomes

$\frac{1}{2}mv_i^2 = \frac{1}{2} m (2v_i)^2 -\frac{k(q)^2}{d}$

$\frac{1}{2} mv_i^2 = 4 [\frac{1}{2}mv_i^2 ]- \frac{k(q)^2}{d}$

$3[\frac{1}{2}mv_i^2 ] = \frac{k(q)^2}{d}$

Making d the subject of the formula

$d = \frac{2k(q)^2}{3mv_i^2}$

$= \frac{2* 8.99*10^9 *(1.602*10^{-19}^2)}{3 * 9.11*10^{-31} *(3.2*10^5)^2}$

$=1.66*10^{-9}m$

6 0

2 years ago

The coefficient of kinetic friction between an object and the surface upon which it is sliding is 0. 10. The mass of the object

lilavasa [31]

The force of friction is 78.4 N

What is force of friction?

Frictional force is the force created when two surfaces come into contact and slide against each other. it is given by the equation:

$F_{f} =$ μ * $F_{n}$

where,

$F_{f}$ = force of friction

μ = coefficient of friction

$F_{n}$ = normal force

Given,

μ $= 0.10, m = 8.0 kg$

We know,

$F_{n} = mg$

$F_{n} = 8.0 * 9.8\\\\ F_{n} = 78.4 N$

Subsituing the values in equation:

$F_{f} =$ μ * $F_{n}$

$F_{f} = 0.10 * 78.4 \\\\F_{f} = 7.84 N$

The force of friction is 78.4 N.

To know more about force of friction, check out:

brainly.com/question/24386803

#SPJ4

4 0

11 months ago

PLEASE HELP ME

Minchanka [31]

Answer:

4 seconds

Explanation:

bullet flies 200m/s. thus 800m/200m=4sec

7 0

3 years ago

Help pls it’s urgent giving brainiest!!

Lorico [155]

Answer:

2nd no. positive.... 3rd no. negitive......

3 0

2 years ago