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2 years ago

The photo shows a pair of figure skaters performing a spin maneuver. The

Physics

1 answer:

solmaris [256]2 years ago

7 0

Answer: the skater on the left pulls the skater on the right closer to him

Explanation:

A PEX this is for increasing their velocity so read carefully

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Before colliding, the momentum of block A is -100 kg*m/, and block B is -150 kg*m/s. After, block A has a momentum -200 kg*m/s.

rjkz [21]

Answer:

Momentum of block B after collision = $-50\ kg\ ms^{-1}$

Explanation:

Given

Before collision:

Momentum of block A = $p_{A1}$ = $-100\ kg\ ms^{-1}$

Momentum of block B = $p_{B1}$ = $-150\ kg\ ms^{-1}$

After collision:

Momentum of block A = $p_{A2}$ = $-200\ kg\ ms^{-1}$

Applying law of conservation of momentum to find momentum of block B after collision $p_{B2}$ .

$p_{A1}+p_{B1}=p_{A2}+p_{B2}$

Plugging in the given values and simplifying.

$-100-150=-200+p_{B2}$

$-250=-200+p_{B2}$

Adding 200 to both sides.

$200-250=-200+p_{B2}+200$

$-50=p_{B2}$

∴ $p_{B2}=-50\ kg\ ms^{-1}$

Momentum of block B after collision = $-50\ kg\ ms^{-1}$

6 0

2 years ago

If the mass of a

mixer [17]

Answer:

The final acceleration becomes (1/3) of the initial acceleration.

Explanation:

The second law of motion gives the relationship between the net force, mass and the acceleration of an object. It is given by :

$F=ma$

m = mass

a = acceleration

According to given condition, if the mass of a sliding block is tripled while a constant net force is applied. We need to find how much does the acceleration decrease.

$a=\dfrac{F}{m}$

Let a' is the final acceleration,

$a'=\dfrac{F}{m'}$

m' = 3m

$a'=\dfrac{F}{3m}$

$a'=\dfrac{1}{3}\times \dfrac{F}{m}$

$a'=\dfrac{1}{3}\times a$

So, the final acceleration becomes (1/3) of the initial acceleration. Hence, this is the required solution.

5 0

3 years ago

what kind of weather is associated with high pressure?How does density,humidity, and air motion compare to that low pressure sys

frutty [35]

Usually nice weather , i dont know the answer to the second part

6 0

2 years ago

Determine the stiffness of the spring to hold the 85-kg crate in the position shown.

GalinKa [24]

Correct position spring hold it

5 0

3 years ago

Rob is studying for an exam. He listed some properties of magnets in a Maglev train.

fredd [130]

The answer is the third one. Maglev is short for Magnetic Levitation in which trains skim on a guideway utilizing the guideline of attractive shock. Every magnet has two shafts. Presently in the event that you play with two magnets, you'll understand that inverse shafts pull in, though comparable posts repulse. This shocking property of magnets is utilized as a part of Maglev trains. However,instead of utilizing lasting magnets, the standard of electromagnetism is utilized to make solid and huge impermanent magnets. At the point when an electric current is gone through a loop of wire, attractive field is created around the curl as indicated by Faraday's laws.

7 0

2 years ago

Read 2 more answers