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Blababa [14]
3 years ago
10

Hydrogen is located in Group 1 on the periodic table. Is it therefore considered a metal?

Chemistry
1 answer:
Natalka [10]3 years ago
3 0
It is the 3rd option because hydrogen is NOT a metal.
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Which of the following salts will be less soluble in 0.10 M NaCl than it is in pure water?
MariettaO [177]

The less soluble salt : PbCl₂

<h3>Further explanation</h3>

Given

0.1 M NaCl

Required

The less soluble salt

Solution

If we see from the answer option, the salt that is more difficult to dissolve in NaCl is PbCl₂ because it has the same ion (Cl)

When PbCl₂ is dissolved in water, ionization will occur

PbCl₂ ⇒ Pb²⁺+ 2Cl⁻

So, when dissolved in NaCl, NaCl itself will be ionized

NaCl ⇒ Na⁺ + Cl⁻

Based on the principle of equilibrium, the addition of an ion (one of the ions is enlarged), the reaction will shift towards the ion that was not added. In addition to this Cl ion, the reaction will shift to the left so that the solubility of PbCl₂ will decrease (the reaction to the right decreases)

8 0
3 years ago
How many atoms of cobalt are in one formula unit of cobalt (III) oxide? one two three six
IrinaK [193]
I believe the correct answer is the second option. There will be two cobalt atoms in one formula unit of cobalt (III) oxide. It has a chemical formula of Co2O3. This compound is does not naturally occur so it is being synthesized. It is mostly used as bleaching agent.
7 0
3 years ago
Read 2 more answers
What is the pH of a solution with a 3.2 x 10−5 M hydronium ion concentration? (5 points)
stiks02 [169]
B. 4.5

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7 0
2 years ago
Write three primary alcohol with the formula C4H8O​
pishuonlain [190]

Answer:

CH2 will be CH-CH2-CH2OH

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3 0
3 years ago
Gaseous methane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 9.6 g of methane is
lianna [129]

Answer:

21.6 g

Explanation:

The reaction that takes place is:

  • CH₄ + 2O₂ → CO₂ + 2H₂O

First we<u> convert the given masses of both reactants into moles</u>, using their <em>respective molar masses</em>:

  • 9.6 g CH₄ ÷ 16 g/mol = 0.6 mol CH₄
  • 64.9 g O₂ ÷ 32 g/mol = 2.03 mol O₂

0.6 moles of CH₄ would react completely with (2 * 0.6) 1.2 moles of O₂. As there are more O₂ moles than required, O₂ is the reactant in excess and CH₄ is the limiting reactant.

Now we <u>calculate how many moles of water are produced</u>, using the <em>number of moles of the limiting reactant</em>:

  • 0.6 mol CH₄ * \frac{2molH_2O}{1molCH_4} = 1.2 mol H₂O

Finally we<u> convert 1.2 moles of water into grams</u>, using its <em>molar mass</em>:

  • 1.2 mol * 18 g/mol = 21.6 g
4 0
2 years ago
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