Answer:
Explanation:
Given
Weight of rifle 
mass of rifle 
mass of bullet 
speed of bullet 
As there is no net force on the bullet-rifle system therefore momentum is conserved




i.e. opposite to the direction of bullet speed
(b)Weight of Man 
Combined weight of man and rifle
mass of man-rifle system 
Now man and rifle combinedly recoil
therefore




Answer:
–2.25 m/s²
Explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = 15 m/s
Distance travelled (s) = 50 m
Final velocity (v) = 0 m/s
Deceleration (a) =?
v² = u² + 2as
0² = 15² + (2 × a × 50)
0 = 225 + 100a
Collect like terms
0 – 225 = 100a
– 225 = 100a
Divide both side by 100
a = –225/100
a = –2.25 m/s²
Thus, the deceleration of the vehicle is –2.25 m/s²
The resistance between A and B is 10 ohms.
Down to the left, down the the right, criss cross!