<h3><u>Answer;</u></h3>
Find the number of 1-foot cubes that fill the fish tank
<h3><u>Explanation;</u></h3>
Volume of a cuboid such as the fish tank is given by the product of length width and height;
Such that; Volume = length × width × height
Similarly, we can count the number of 1 foot cube that can fill the fish tank.
And since each cube has a volume of 1 cubic ft, then the number of cubes will be equivalent to the volume of the fish tank in cubic ft.
Answer:
b) 2H+(aq) + 2C1-(aq) + Zn(s) → H2(g) + Zn2+(aq) + 2Cl-(aq)
Explanation:
The equation is given as;
2HCl(aq) + Zn(s) + H2(g) + ZnCl2(aq)
In writing an ionic equation, only the aqueous compounds dissociates into ions. This means HCl and ZnCl2 would dissociate to form ions.
This is given as;
2H+ + 2Cl- + Zn(s) --> H2(g) + Zn2+ + 2Cl-
The correct option is;
b) 2H+(aq) + 2C1-(aq) + Zn(s) → H2(g) + Zn2+(aq) + 2Cl-(aq)
K₃PO₄ → 3K⁺ (aq) + PO₄³⁻(aq)
One mole of PO₄³⁻ ion gets dissociated from one mole of K₃PO₄
As per the definition of Avogadro's number, 1 mole = 6.022 x 10²³ ions
One mole of PO₄³⁻ ions x (6.022 x 10²³ ions/ 1 mole of PO₄³⁻ ions )
= 6.022 x 10²³ ions
Therefore , there are 6.022 x 10²³ PO₄³⁻ ions in a mole of K₃PO₄.
Answer:
Pentafluorobenzene: 11,92 min
Benzene: 12,14 min
Explanation:
<em>Retention time of pentafluorobenzene is 12,98 min and 13,20 min of benzene.</em>
The adjusted retention time is the time an analyte spends in the column not the stationary phase. As time of unretained solute is 1,06 min the adjusted retention time for an analyte is:
tr' = tr - 1,06min
For pentafluorobenzene:
tr' = 12,98min - 1,06min = <em>11,92 min</em>
For benzene:
tr' = 13,20 - 1,06min = <em>12,14 min</em>
<em></em>
I hope it helps!
