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goldenfox [79]
2 years ago
15

On an unknown planet in the outer-reaches of the solar system, a pendulum with a 12 g bob and a string length of 4 m oscillates

with a period of 2 seconds. what is the value for the acceleration due to gravity (g) on this planet? (outcome 1)
Physics
1 answer:
11Alexandr11 [23.1K]2 years ago
3 0

The acceleration due to gravity (g) on this planet is 39.44 m/s²

<h3>What is solar system?</h3>

Solar system consists of all the planets and the most importantly the center of the solar system is Sun.

Given is an unknown planet in the outer-reaches of the solar system, a pendulum with a 12 g bob and a string length of 4 m oscillates with a period of 2 seconds.

The time period of the pendulum is

T = 2π √l/g

Squaring both sides, we get

l/g = T² / 4π²

g = 4π²l/ T²

Substitute Time period T = 2s and  length l = 4m,  we get

g = 4π²x 4/ 2²

g =39.44 m/s²

Thus, the acceleration due to gravity on this planet is 39.44 m/s²

Learn more about solar system.

brainly.com/question/12075871

#SPJ1

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block of mass 5kgriding on a horizontal frictionlessxy-plane surface is subjected tothree applied forces:→F1= 12√2N[ 45◦]→F2= (8
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(i) See attached image for the drawing

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