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2 years ago

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On an unknown planet in the outer-reaches of the solar system, a pendulum with a 12 g bob and a string length of 4 m oscillates

with a period of 2 seconds. what is the value for the acceleration due to gravity (g) on this planet? (outcome 1)

1 answer:

11Alexandr11 [23.1K]2 years ago

3 0

The acceleration due to gravity (g) on this planet is 39.44 m/s²

<h3>What is solar system?</h3>

Solar system consists of all the planets and the most importantly the center of the solar system is Sun.

Given is an unknown planet in the outer-reaches of the solar system, a pendulum with a 12 g bob and a string length of 4 m oscillates with a period of 2 seconds.

The time period of the pendulum is

T = 2π √l/g

Squaring both sides, we get

l/g = T² / 4π²

g = 4π²l/ T²

Substitute Time period T = 2s and length l = 4m, we get

g = 4π²x 4/ 2²

g =39.44 m/s²

Thus, the acceleration due to gravity on this planet is 39.44 m/s²

Learn more about solar system.

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sveta [45]

Answer:

The correct answer is A

Explanation:

The question requires as well the attached image, so please see that below.

Coulomb's Law.

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$|F|=k \cfrac{q_1 q_2}{r^2}$

Thus if we decrease the distance by half we have

$r_1 =\cfrac r2$

So we get

$|F|=k \cfrac{q_1 q_2}{r_1^2}$

Replacing we get

$|F|=k \cfrac{q_1 q_2}{(r/2)^2}\\|F|=k \cfrac{q_1 q_2}{r^2/4}$

We can then multiply both numerator and denominator by 4 to get

$|F|=k \cfrac{4q_1 q_2}{r^2}$

So we have

$|F|=4 \left(k \cfrac{q_1 q_2}{r^2}\right)$

Thus if we decrease the distance by half we get four times the force.

Then we can replace the second condition

$q_{2new} =2q_2$

So we get

$|F|=k \cfrac{q_1 q_{2new}}{r_1^2}$

which give us

$|F|=k \cfrac{q_1 2q_2}{r_1^2}\\|F|=2\left(k \cfrac{q_1 q_2}{r_1^2}\right)$

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3 years ago

Read 2 more answers

A car is moving down the street at 53km/h. A child suddenly runs into the street. If it takes the driver 0.75 sec to react and a

BARSIC [14]

Answer:

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Explanation:

Convert kilometers to meters: 53km/h x 1000 = 53,000m/h

Convert hours to seconds: 53m/h / 3600 =14.72m/s

14.72 (.75) = 11.04

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2 years ago

A cylinder contains 3.5 L of oxygen at 350 K and 2.7 atm . The gas is heated, causing a piston in the cylinder to move outward.

Effectus [21]

Answer:

The pressure is $P_2 = 1.84 \ a.t.m$

Explanation:

From the question we are told that

The first volume of is $v_1 = 3.5 \ L$

The first pressure is $P_1 = 2.7 \ a.t.m$

The first temperature is $T_1 = 350 \ K$

The new temperature is $T_2 = 620 \ K$

The new volume is $V_2 = 9.1 \ a.t.m$

Generally according to the combined gas law we have that

$\frac{P_1 V_1 }{T_1 } = \frac{P_2 V_2 }{T_2 }$

=> $P_2 = \frac{P_1 * V_1 * T_2 }{T_1 * V_2 }$

=> $P_2 = \frac{ 2.7 * 3.5 * 620 }{ 350 * 9.1 }$

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3 years ago

What is the average velocity in m/y of a tectonic plate that has traveled 9000 km to the south in 60 million years

alexandr402 [8]

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3 years ago

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docker41 [41]

Answer:

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divide both sides by 102.1kg

8.45m/s = recoil speed

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