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3 years ago

32. For each of the listed parts of a power plant, make a selection to indicate in what

Physics

1 answer:

k0ka [10]3 years ago

7 0

Answer: a. boiler - I. part of a coal-fired power plant.

b. combustion chamber - I. part of a coal-fired power plant.

c. condenser - III. part of a coal-fired power plant and part of a nuclear power plant.

d. control rod - I. part of a coal-fired power plant.

e. generator- III. part of a coal-fired power plant and part of a nuclear power plant.

f. turbine - III. part of a coal-fired power plant and part of a nuclear power plant.

Explanation:

a. Boiler: It is used in the coal power plant to heat the water used for producing electricity. The boiler keeps the temperature of water or steam at a desired level.

b. Combustion chamber: It is used for combustion of coal and using thermal energy for electricity generation.

c. Condenser; It is used in both nuclear and coal power plants. It condense and receive from the turbine.

d. Control rod: It is used in the nuclear power plant for controlling the nuclear fission and fusion reactions of heavy metals.

e. Generator: It converts the thermal energy into electrical energy.

f. Turbine: The turbine blades move with the effect of steam or any form of energy and the energy so produce is used for generating electricity in generator.

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A fixed 15.3-cm-diameter wire coil is perpendicular to a magnetic field 0.77 T pointing up. In 0.20 s , the field is changed to

maksim [4K]

Answer:

Induced emf will be 0.468 volt

Explanation:

We have given diameter of wire d = 15.3 cm

So radius $r=\frac{d}{2}=\frac{15.3}{2}=7.65cm$

So area $A=\pi r^2=3.14\times (7.65)^2=183.76\times 10^{-4}m^2$

Change in magnetic field dB = 0.26 - 0.77 = -0.51 T

Time for change in magnetic field dt = 0.26 sec

We know that emf is given by $e=\frac{-d\Phi }{dt}=-A\frac{dB}{dt}=-183.76\times 10^{-4}\times \frac{-0.51}{0.2}=0.0468volt$

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3 years ago

A horizontal wire of length 0.53 m. carrying a current of 7.5 A. is placed in a uniform external magnetic field. When the wire i

Lady_Fox [76]

Answer:

3.4 mT

Explanation:

L = 0.53 m

i = 7.5 A

Theta = 19 degree

F = 4.4 × 10^-3 N

Let B be the strength of magnetic field.

Force on a current carrying conductor placed in a magnetic field.

F = i × L × B × Sin theta

4.4 × 10^-3 = 7.5 × 0.53 × B × Sin 19

B = 3.4 × 10^-3 Tesla

B = 3.4 mT

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3 years ago

What name is used for a high-power variable resistor?

const2013 [10]

The answer would be C: Rheostat. :)

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3 years ago

Read 2 more answers

Set up differential equation of angular S.H.M

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Answer:

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3 years ago

A series of pulses, each of amplitude 0.1m , is sent down a string that is attached to a post at one end. The pulses are reflect

sp2606 [1]

The net displacement at a point on the string where the pulses cross is 0.2 m.

The term "displacement" refers to a shift in an object's position. It has a magnitude and a direction, making it a vector quantity. An arrow pointing from the starting point to the finishing point serves as its symbol.

A string that is connected to a post at one end is used to transmit a sequence of pulses, each measuring 0.1 meters in amplitude.

At the post, the pulses are reflected and return along the string without losing any of their amplitude.

Now, let's say the ends are free.

There is no inversion on reflection if the end is free. The amplitude at their intersection is 2A.

Now, since A = 0.1 m

Then, 2A = 2(0.1) = 0.2 m

As a result, the net displacement at the string's intersection of two pulses is 0.2 m.

The correct option is (c).

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brainly.com/question/3613222

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2 years ago