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3 years ago

32. For each of the listed parts of a power plant, make a selection to indicate in what

Physics

1 answer:

k0ka [10]3 years ago

7 0

Answer: a. boiler - I. part of a coal-fired power plant.

b. combustion chamber - I. part of a coal-fired power plant.

c. condenser - III. part of a coal-fired power plant and part of a nuclear power plant.

d. control rod - I. part of a coal-fired power plant.

e. generator- III. part of a coal-fired power plant and part of a nuclear power plant.

f. turbine - III. part of a coal-fired power plant and part of a nuclear power plant.

Explanation:

a. Boiler: It is used in the coal power plant to heat the water used for producing electricity. The boiler keeps the temperature of water or steam at a desired level.

b. Combustion chamber: It is used for combustion of coal and using thermal energy for electricity generation.

c. Condenser; It is used in both nuclear and coal power plants. It condense and receive from the turbine.

d. Control rod: It is used in the nuclear power plant for controlling the nuclear fission and fusion reactions of heavy metals.

e. Generator: It converts the thermal energy into electrical energy.

f. Turbine: The turbine blades move with the effect of steam or any form of energy and the energy so produce is used for generating electricity in generator.

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A rope connects boat A to boat B. Boat A starts from rest and accelerates to a speed of 9.5 m/s in a time t = 47 s. The mass of

Contact [7]

Answer: 339.148N

Explanation:

Data

Time (t) = 47s

U = 0m/s

V = 9.5m/s

Mass of B = 540kg

Frictional force on B = 230N

Both boats are connected so if A moves, B moves too.

Acceleration of boat A =?

Using equation of motion,

V = u + at

9.5 = 0 + a*47

a = 9.5 / 47

a = 0.2021 m/s²

The force required to accelerate boat B since it's the same force moving both boats =?

F = Mass * acceleration

F = 540 * 0.2021 = 109.14N

A frictional force of 230N exists on boat B

Total force (Tension) = frictional force + normal force = (109.15 + 230)N = 339.148N

7 0

3 years ago

Two workers are sliding 350 kgkg crate across the floor. One worker pushes forward on the crate with a force of 390 NN while the

svetoff [14.1K]

Answer:

$\mu_k=0.18$

Explanation:

First, we write the equations of motion for each axis. Since the crate is sliding with constant speed, its acceleration is zero. Then, we have:

$x: T+F-f_k=0\\\\y:N-mg=0$

Where T is the tension in the rope, F is the force exerted by the first worker, f_k is the frictional force, N is the normal force and mg is the weight of the crate.

Since $f_k=\mu_k N$ and $N=mg$ , we can rewrite the first equation as:

$T+F-\mu_k mg=0$

Now, we solve for $\mu_k$ and calculate it:

$\mu_k=\frac{T+F}{mg}\\ \\\mu_k =\frac{220N+390N}{(350kg)(9.8m/s^{2})} =0.18$

This means that the crate's coefficient of kinetic friction on the floor is 0.18.

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4 years ago

which of these statements best explains why the difference between summer and winter temperatures is greatet in Russia thanin FL

MaRussiya [10]

I don't know your statement, but one explanation for this is that Russia is mostly located on land, away from water and Florida is surrounded by water.

Water takes up the heat from the environment, so it has the effect of making the temperatures of objects around it milder: cooling down when hot, warming up when too cold.

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3 years ago

Large waves produced by earthquakes

galina1969 [7]

Answer:

Explanation:

If the earthquake occus in the ocean, it can push up powergul waves.

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3 years ago

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23. The force required to accelerate a 2.0-kilogram

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