Answer:
v₂> v₃ velocity canoe is more than velocity fishing boat
Explanation:
For this exercise we must define a system consisting of the girl, Sally and the boat, in one case the canoe and in the other the fishing boat; for this system we can use moment conservation
Initial moment. Before the jump
p₀ = (M + m₂) v
Final moment. After the jump
= M v₁ - m₂ v₂
Where m and v are the masses and speed of the canoe
p₀ = p_{f}
(M + m₂) v = M v₁ - m₂ v₂
In the case of changing the canoe for the heaviest fishing boat, the final moment is
p_{f} = M v₁ - m₃ v₃
p₀ = p_{f}
(M + m₃) v = M v₁ - m₃ v₃
Since the canoe is stopped the speed v = 0, we write the speed of each boat
Canoe
0 = M v₁ - m₂ v₂
v₂ = M / m₂ v₁
Fishing boat
0 = M v₁ - m₃ v₃
v₃ = M / m₃ v₁
Since the masses of the fishing boat (m₃) is greater than the mass of the canoe (m₂) the speed of the fishing boat is less than the speed of the canoe, we can find the relationship between the two speeds
v₂ / v₃ = m₃ / m₂
Here you can see what v₂> v₃ velocity canoe is more than velocity fishing boat
Answer:
Physical quantities are the substances which can be measured. By measuring physical quantities, we can measure the mass, weight and other physical properties
Answer: The height of its fourth bounce = 0.43m
Explanation:
The coefficient of restitution denoted by (e), is the ratio that shows the final velocity to initial relative velocity between two objects after collision
IT is given by the formula in terms of height as
Coefficient of Restitution, e = √(2gh))/√(2gH) = √(h/H)
Where
Coefficient of Restitution, e= 0.821
H = 2.07 m
At fourth bounce , we have that
Coefficient of Restitution, e⁴ =√(h₄/H)
Putting the given values and solving , we have,
e⁴ =√(h₄/H)
= 0.821⁴ = √(h₄/2.07)
(0.821⁴ )² =h₄/2.07
0.2064 x 2.07 = 0.427 = 0.43
At fourth bounce, h₄ height = 0.43m
Answer:
Part A: 
to two significant figures
Part B: 
to two significant figures
Part C: 
to two significant figures
Explanation:
Given that :
mass of the hydrogen = 0.30 g
the molar mass of hydrogen gas molecule = 2 g/mol
we all know that:
number of moles = mass/molar mass
number of moles = 0.30 g /2 g/mol
number of moles = 0.15 mol
For low temperature between the range of 50 K to 100 K, the specific heat at constant volume for a diatomic gas molecule = 
For Part A:
to two significant figures
Part B. For hot temperature, 
to two significant figures
Part C. For an extremely hot temperature, 
to two significant figures
Answer:work is done, and temperature increases
Explanation:
In an adiabatic process, when gases are compressed, work is done on the liquid and the temperature increases
