10) For a horizontally launched projectile, decreasing the velocity of the
1 answer:
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Answer:
The wavelength of the visible line in the hydrogen spectrum is 434 nm.
Explanation:
It is given that, the wavelength of the visible line in the hydrogen spectrum that corresponds to n₂ = 5 in the Balmer equation.
For Balmer series, the wave number is given by :
R is the Rydberg's constant
For Balmer series, n₁ = 2. So,
or
So, the wavelength of the visible line in the hydrogen spectrum is 434 nm. Hence, this is the required solution.