Answer:
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Pretty sure it's C) condensation because all of the others required heat to be added
Answer:
The answer is
The wavelength of the light is 557.2 x 10⁻⁻⁹nm
Explanation:
The wavelength of a wave is the distance between adjacent troughs and crests while the frequency of a wave is the number of completed cycles that pass a given per unit time
Electromagnetic radiation, such as light is usually described n terms of its frequency and wavelength
The equation relating the three quantities of speed of light, frequency and wavelength is as follows
Speed of light, c = Frequency of the light wave, ν × Wavelength of the light, λ
That is c = ν × λ
Where c = 299792458 m/s, v = 5.38 x 10¹⁴ Hz
Therefore the wavelength = = 5.572 x 10⁻⁷ m 557.2 x 10⁻⁻⁹nm
Answer:
C.
Explanation:
I think it's c please let me know if it's incorrect
Answer:
a) E = σ / 2 ε₀ =
Q / 2A ε₀, b) E = 2Q/A ε₀
Explanation:
For this exercise we can use Gauss's Law
Ф = E. dA = / ε₀
Let us define a Gaussian surface as a cylinder with the base parallel to the plane. In this case, the walls of the cylinder and the charged plate have 90 degrees whereby the scalar product is zero, the normal vector at the base of the cylinder and the plate has zero degrees whereby the product is reduced to the algebraic product
Φ = E dA = q_{int} / ε₀ (1)
As they indicate that the plate has an area A, we can use the concept of surface charge density
σ = Q / A
Q = σ A
The flow is to both sides of loaded plate
Φ = 2 E A
Let's replace in equation 1
2E A = σA / ε₀
E = σ / 2 ε₀ =
Q / 2A ε₀
This is in the field at point P.
b) Now we have two plates each with a load Q and 3Q respectively and they ask for the field between them
The electric field is a vector quantity
E = E₁ + E₂
In the gap between the plates the two fields point in the same direction whereby they add
σ₁ = Q / A
E₁ = σ₁ / 2 ε₀
For the plate 2
σ₂ = -3Q / A = -3 σ₁
E₂ = σ₂ / 2 ε₀
E₂ = -3 σ₁ / 2 ε₀
The total field is
E = σ₁ / 2 ε₀ + 3 σ₁ / 2 ε₀
E = σ₁ / 2 ε₀ (1+ 3)
E = 2 σ₁ / ε₀
E = 2Q/A ε₀