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Keith_Richards [23]
3 years ago
14

(Paper Chromatography)

Chemistry
1 answer:
allsm [11]3 years ago
4 0
1. The newspaper solution that would work best with inks is alcohol since alcohol can dissolve inks.
2. Water can be used to carry salts since salts are soluble in water.
3. Oils can be used to carry fatty acids since they're both hydrophobic substances.<span />
You might be interested in
How many moles of n are in 0.185 g of n2o?
pickupchik [31]

The mass of N_{2}O is 0.185 g.

To calculate the number of moles first calculate the molar mass of N_{2}O .

M_{N_{2}O}=2\times M_{N}+M_{O}

Molar mass of nitrogen and oxygen is 14 g/mol and 16 g/mol respectively

Thus, M_{N_{2}O}=2\times 14 g/mol+18 g/mol=44 g/mol

Now, number of moles can be calculated from mass and molar mass as follows:

n=\frac{m}{M}=\frac{0.185 g}{44 g/mol}=0.0042 mol

Therefore, number of moles of 0.185 g N_{2}O is 0.0042 mol.

8 0
3 years ago
Read 2 more answers
What are the principal alloy elements of an AISI 4340 steel? How much carbon does it have? Is it hardenable? By what techniques?
amid [387]

Answer:

The principal elements are Iron, Nickel, Chromium

It has 0.37% to 0.43% Carbon

It is hardenable.

It can be hardened by cold working, annealing, quenching.

Explanation:

A)

The chemical composition of AISI 4340 Steel are as follows:

Iron  ---  95% to 96%

Nickel  ---  1.6% to 2.0%

Chromium  ---  0.7% to 0.9%

Manganese  ---  0.6% to 0.8%

Carbon  ---  0.37% to 0.43%

Molybdenum  ---  0.2% to 0.3%

Silicon  ---  0.15% to 0.30%

Sulfur  ---   0.040%

Phosphorous  --- 0.0350%

So, the principal alloy elements from this composition are <u>Iron, Nickel and Chromium</u>

B)

The carbon content in this alloy is <u>0.37% to 0.43%</u>

C)

<u>Yes, it can be hardened</u>.

D)

<u>It can be Hardened by Cold Working, Annealing or Quenching</u>.

3 0
2 years ago
The radius of a single atom of a generic element X is 169 picometers (pm) and a crystal of X has a unit cell that is body-center
Virty [35]

The volume of the unit cell is 2.67 x 10⁻²⁸ m³.

<h3>What is the volume of a unit cell of a body-centered cubic crystal?</h3>

In a body-centered cubic unit cell, the volume occupied by the particles of the substance is about 68% of the total unit cell.

Assuming that a single atomic a sphere, the volume is:

Volume(atom) = 4/3 x π x r³

Volume(atom) = 4/3 x π x (169 x 10⁻¹²)³

Volume(atom) = 2.02 x 10⁻²⁹ m³

There are a total of 9 atoms in a body-centered unit cell, so the total volume occupied by atoms is:

2.02 x 10⁻²⁹ x 9

= 1.82 x 10⁻²⁸ m³

Volume of cell = (1.15 x 10⁻²⁸ ) / 0.68

Volume of cell = 2.67 x 10⁻²⁸ m³

Therefore, the volume of the unit cell is 2.67 x 10⁻²⁸ m³.

Learn more volume of unit cells at: brainly.com/question/1594030

#SPJ1

8 0
2 years ago
Which reacts faster, rock salt or grains of salt? Why?​
sweet-ann [11.9K]

Answer:

salt

Explanation:

because it has a much larger volume ratio

5 0
3 years ago
How many atoms are there in 7.80 moles of germanium
Orlov [11]
<h3>Answer:</h3>

4.70 × 10²⁴ atoms Ge

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>Explanation:</h3>

<u>Step 1: Define</u>

7.80 mol Ge

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

\displaystyle 7.80 \ mol \ Ge(\frac{6.022 \cdot 10^{23} \ atoms \ Ge}{1 \ mol \ Ge} ) = 4.69716 × 10²⁴ atoms Ge

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

4.69716 × 10²⁴ atoms Ge ≈ 4.70 × 10²⁴ atoms Ge

8 0
2 years ago
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