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melomori [17]
3 years ago
12

Help please ! Sishsoshsishsjdhshishd

Mathematics
1 answer:
Artyom0805 [142]3 years ago
8 0
(-1,-5) is the answer top left.
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A set of data has a normal distribution with a mean of 5.1 and standard deviation of 0.9. Find the percent of data between 6.0 a
jolli1 [7]

The percent data between 6.0 and 6.9 would be 13.59%. Here’s the complete solution for this specific problem.

<span>z = (X - Mean)/SD </span><span>
<span>z1 = (6 - 5.1)/09 = + 1 </span>
<span>z2 = (6.9 - 5.1)/09 = + 2 </span>
<span>Required Percent = P(6 < X < 6.9)*100 </span>
<span>= P(1 < z < 2)*100 </span>
<span>= [P(z < 2) - P(z < 1)]*100 </span>
<span>= [0.9772 - 0.8413]*100 </span>
<span>= 0.1359*100 </span>
<span>= 13.59%

I am hoping that this has answered your query.</span></span>

5 0
3 years ago
Solve.. pls need this quick.. I'll mark you as brainliest!!!
UkoKoshka [18]

Answer:

b. 896

Step-by-step explanation:

just put the numbers on the choice to know the right answer. here when you put 896 in <u>    </u>*27/14/72=24 you will get the right answer which is 24. so the answer is 896.

5 0
3 years ago
Read 2 more answers
I don't know what to do
anyanavicka [17]
If you don't..I don't either by answering your question...
8 0
3 years ago
I need help with this question for homework.
Leviafan [203]
Here's the method on the first one (36)

The ratio is \frac{72}{126}=\frac{36}{63}=\frac{12}{21}=\frac{4}{7}, hence if we call xthe number below 36, we will have \frac{36}x=\frac{72}{126}=\frac{4}7 hence x=\frac{36\cdot7}4=63

I_72__I_36_I_24_I_12_I
<span>I_126_I_63_I_42_I_21_I

</span>
3 0
3 years ago
Read 2 more answers
(7x^3-6+5x^2)+(6x^4-2-6x^3)+(4x^2+3x^4+8x)
Anit [1.1K]
9x^4+x^3+9x^2+8x-8, I believe
4 0
3 years ago
Read 2 more answers
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