<u>Let's consider the facts at hand</u>:
- By Vertical Angle Theorem ⇒ ∠BCE = ∠DCF
- ∠BEC = ∠DFC
- Sides BE = DF
<u>Based on the diagram, triangles BCE and triangles DCF are similar</u>
⇒ based on the Angle-Angle theorem
⇒ since ∠BCE = ∠DCF and ∠BEC = ∠DFC
⇒ the two triangles are similar
Hope that helps!
<em>Definitions of Theorem I used:</em>
- <u><em>Vertical Angle Theorem: </em></u><em>opposite angles of two intersecting lines must be equal</em>
- <u><em>Angle-Angle Theorem:</em></u><em> if two angles of both triangles are equal, then the given triangles must be similar</em>
<em />
Answer:
Domain is 0 to 50.
Step-by-step explanation:
Answer:
h = 66
Step-by-step explanation:
We are given the equation of one variable h and we have to solve the equation for h.
The equation is given by 
⇒ 
{Adding 17 to both sides}
⇒ 
⇒ h = 22 × 3 {Since we know that if 
then we can write 
}
⇒ h = 66 (Answer)
Answer: root t(5)/19300
Explanation:
P(t) = 19300(5)^t
P-1(t) = root t(5)/19300
