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charle [14.2K]
2 years ago
11

Helpppppp!!!!

Physics
2 answers:
Advocard [28]2 years ago
5 0

Below are the examples of work being done on an object

Carrying a box up a flight of stairs.

Lifting a bag of groceries.

Lifting a rock off the ground.

Pushing a grocery cart through the store.

<h3>Workdone</h3>

Work is said to be done when a force applied moves a distance

Work done = force × distance

Learn more about work done:

brainly.com/question/18762601

rewona [7]2 years ago
4 0

Answer:

A mover carries a box up a flight of stairs.

A mover carries a box across a room.

Wind blows a pool chair across the yard.

A weightlifter lifts a barbell off the ground.

These are the only cases in which work is being done. The Formula of Work is:

Work= Force applied x Distance moved.

In all of these cases force is being applied and the object on which the force is being applied move in a horizontal or Vertical direction.  Thus Work is done !

You might be interested in
Convert 15 litre into cubic metre​
atroni [7]

Answer:

0.015m^3

Explanation:

1 m^3 = 1000 liters

x m^3 = 15 liters

Cross multiply

xm^3 x 1000 l = 15 l

Divide both sides by 1000

xm^3 x1000/1000 = 15/1000

xm^3 = 0.015m^3

Therefore 15 liter = 0.015m^3

5 0
3 years ago
How long does a car (1000 kg) have a speed of 30 m/s from a rest if the engine power is 10kw
Lemur [1.5K]

Answer: 90.1 s

Explanation:

Use equation for power:

P=F*V

Use eqation for force:

F=ma

F---force

V---velocity

Vr=om/s

V=30m/s

m=1000kg

P=10000W

---------------------------

P=FV

F=P/V

F=10000W/30m/s

F=333.33N

Use equation for force to find accelartaion.

F=ma

a=F/m

a=333.33N/1000kg

a=0.333 m/s²

Use equation for accelaration to find out time:

a=(V-Vs)/t

t=(V-Vs)/a

t=(30m/s)/(0.333m/s²)

t=90.09 s≈90.1 s

------------------------

5 0
3 years ago
PLEASE NEED AN ANSWER SO I CAN SUBMIT IT!!! THANK YOU IN ADVANCE (will give brainliest)
alexandr402 [8]

Answer:

Im only 12 and i need the points so ima try my best.

Explanation:

574.780616 m6 kg3 s-6 K-3 mol-3

6 0
3 years ago
Irreversible damage to the liver due to long term alcohol abuse is called:
damaskus [11]

Answer:

A, Cirrhosis

Explanation:

3 0
3 years ago
Read 2 more answers
A 2.61 g lead weight, initially at 11.1 ∘C, is submerged in 7.67 g of water at 52.6 ∘C in an insulated container. What is the fi
sleet_krkn [62]

Answer:

Equilibrium temperature will be T=52.2684^{\circ}C

Explanation:

We have given weight of the lead m = 2.61 gram

Let the final temperature is T

Specific heat of the lead c = 0.128

Initial temperature of the lead = 11°C

So heat gain by the lead = 2.61×0.128×(T-11°C)

Mass of the water m = 7.67 gram

Specific heat = 4.184

Temperature of the water = 52.6°C

So heat lost by water = 7.67×4.184×(T-52.6)

We know that heat lost = heat gained

So 2.61\times 0.128\times (T-11)=7.67\times 4.184\times (52.6-T)

0.334T-3.67=1688-32.031T

T=52.2684^{\circ}C

5 0
2 years ago
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