Answer is: Check for the presence of alpha, beta, and gamma particles.
1) Alpha particle is nucleus of a helium-4 atom, which is made of two protons and two neutrons.
Alpha decay is radioactive decay in which an atomic nucleus emits an alpha particle (helium nucleus) and transforms into an atom with an atomic number that is reduced by two and mass number that is reduced by four.
2) Beta decay is radioactive decay in which a beta ray and a neutrino are emitted from an atomic nucleus.
There are two types of beta decay: beta minus and beta plus.
3) During gamma emission the nucleus emits radiation without changing its composition.
Answer:
In direct observation, EVERY INDIVIDUAL in a population is counted. In indirect observation, SIGNS OF AN INDIVIDUAL, such as tracks or nests, are counted.
Explanation:
Direct observation is to involve looking at the actual behavior or occurrence so for your question it would be every individual.
Indirect observation is a result of that occurrence, so for your question it would be the signs of an individual.
I can't help you with the paper because it is to small.
A can of peas and carrots has 2 typed of matter (peas and carrots) that can be separated my physical means. (You can do it with a spoon). Another example= chicken noodle soup, a snickers bar
<u>Answer:</u> The rate of the reaction when concentrations are changed is 
<u>Explanation:</u>
For the given chemical reaction:

The given rate law of the reaction follows:
![\text{Rate}_1=k\frac{[A][C]^2}{[B]^{1/2}}](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D_1%3Dk%5Cfrac%7B%5BA%5D%5BC%5D%5E2%7D%7B%5BB%5D%5E%7B1%2F2%7D%7D)
We are given:

When the concentrations are changed:
New concentration of A = 2A (Concentration is doubled)
New concentration of C = 2C (Concentration is doubled)
New concentration of B = 3B (Concentration is tripled)
The new rate law expression becomes:
![\text{Rate}_2=k\frac{[2A][2C]^2}{[3B]^{1/2}}\\\\\text{Rate}_2=\frac{2\times 2^2}{3^{1/2}}\times (k\frac{[A][C]^2}{[B]^{1/2}})\\\\\text{Rate}_2=4.62\times (\text{Rate}_1)\\\\\text{Rate}_2=4.62\times 1.12\times 10^{-2}\\\\\text{Rate}_2=5.17\times 10^{-2}M/s](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D_2%3Dk%5Cfrac%7B%5B2A%5D%5B2C%5D%5E2%7D%7B%5B3B%5D%5E%7B1%2F2%7D%7D%5C%5C%5C%5C%5Ctext%7BRate%7D_2%3D%5Cfrac%7B2%5Ctimes%202%5E2%7D%7B3%5E%7B1%2F2%7D%7D%5Ctimes%20%28k%5Cfrac%7B%5BA%5D%5BC%5D%5E2%7D%7B%5BB%5D%5E%7B1%2F2%7D%7D%29%5C%5C%5C%5C%5Ctext%7BRate%7D_2%3D4.62%5Ctimes%20%28%5Ctext%7BRate%7D_1%29%5C%5C%5C%5C%5Ctext%7BRate%7D_2%3D4.62%5Ctimes%201.12%5Ctimes%2010%5E%7B-2%7D%5C%5C%5C%5C%5Ctext%7BRate%7D_2%3D5.17%5Ctimes%2010%5E%7B-2%7DM%2Fs)
Hence, the rate of the reaction when concentrations are changed is 