Ask question

Ask question

All categories

2 years ago

12

Help me please

ss="latex-formula">

❝How did i go from growing up to breaking down❞-ts

2 answers:

poizon [28]2 years ago

7 0

Answer:

2

Explanation:

A rigid body is not elastic.

i.e. it does not change shape.

ivolga24 [154]2 years ago

4 0

Infinite

Lets see how

Elasticity is Young's modulus

Young's modulus is Stress/Strain.

For a rigid body strain is 0.

So Young's modulus is infinite

You might be interested in

Isla made a diagram to compare X-rays and radio waves.

pickupchik [31]

A: Has a higher frequency --> X-rays

B: Travels at the same speed --> Both

C: Has a longer wavelength --> Radio waves

Explanation:

Electromagnetic waves are waves consisting of oscillations of electric and magnetic field in a direction perpendicular to the direction of motion of the wave.

Electromagnetic waves travel at the speed of light ( $c=3.0\cdot 10^8 m/s$ ) in a vacuum, and they are transverse in nature (the direction of vibration is perpendicular to the direction of propagation).

Electromagnetic waves are classified into different types according to their wavelength and frequency. In order from shortest to longest wavelength (and so, from highest to lowest frequency, since frequency is inversely proportional to the wavelength), we have:

Gamma rays

X-rays

Ultraviolet radiation

Visible light

Infrared radiation

Microwaves

Radio waves

Therefore, we can no says that:

X-rays: has a higher frequency than Radio waves

Radio waves: have a longer wavelength than x-rays

Both: they travel at the same speed

Therefore, the correct pairing is:

A: Has a higher frequency --> X-rays

B: Travels at the same speed --> Both

C: Has a longer wavelength --> Radio waves

Learn more about electromagnetic waves:

brainly.com/question/9184100

brainly.com/question/12450147

#LearnwithBrainly

6 0

3 years ago

Two equipotential surfaces surround a +3.10 x 10-8-c point charge. how far is the 290-v surface from the 41.0-v surface?

MrMuchimi

T<span>he equation to be used here to determine the distance between two equipotential points is:
V = k * Q / r

where v is the voltage of the point, k is a constant, Q is charge of the point measured in coloumbs and r is the distance.
In this case, we can use ratio of proportions to determine the distance between the two points. in this respect,

Point 1:
V = k * Q / r = 290
r = k*Q/290 ; kQ = 290r

Point 2:
V = k * Q / R = 41
R = k*Q/41
from equation 10 kQ = 290r
R = 290/(41)= 7.07 m
The distance between the two points then is equal to 7.07 m.

</span>

8 0

3 years ago

What is the magnitude of velocity called?

PIT_PIT [208]

The magnitude<span> of a </span>velocity<span> vector is </span>called<span> speed. Supposethat a wind is blowing in from the direction at a speed of 50 km/h. (This meansthat the direction from which the wind blows is west of the northerly direction.) Apilot is steering a plane in the direction at an airspeed (speed in still air) of250 km/h

</span>

3 0

3 years ago

A Ping-Pong ball with mass 2.5 g is attached by a thread to the bottom of a beaker. When the beaker is filled with water so that

dimaraw [331]

Answer:

0.022m or 2.2cm

Expxlanation:

Step 1:

Data obtained from the question. This includes:

Mass (m) = 2.5g = 2.5/1000 = 2.5x10^-3Kg

Tension (T) = 0.029 N

Density (ρ) = 1000 kg/m3

Acceleration due to gravity (g) = 9.81 m/s2

Diameter (d) =?

Step 2:

Finding an expression to calculate the diameter of the ball. This is illustrated below:

Tension = weight displaced - weight of the ball

Weight displaced = Mass of water x acceleration due to gravity

Mass of water = Density x volume

Mass of water = ρxV

Weight displaced = ρxVxg = ρVg

Weight of the ball = Mass of the ball x acceleration due to gravity

Weight of the ball = mg

Therefore,

Tension = weight displaced - weight of the ball

T = ρVg - mg

Make V the subject of the formula

T = ρVg - mg

T + mg = ρVg

Divide both side by ρg

V = ( T + mg) /ρg. (1)

Recall that the ball is spherical in shape and the Volume of a sphere is given by

V = 4/3πr^3

Radius (r) = diameter (d) /2

V = 4/3π(d/2)^3

V = 4/3πd^3/8

V = πd^3 /6

Substituting the value of V into equation 1, we have

V = ( T + mg) /ρg

πd^3 /6 = ( T + mg) /ρg.

Making d the subject of the formula, we have:

πd^3 /6 = (T + mg) /ρg.

d^3 = 6(T + mg) /πρg.

Taking the cube root of both sides

d = [6(T + mg) /πρg]^1/3

Step 3:

Determination of the diameter of the ball. This is illustrated below:

T = 0.029 N

m = 2.5x10^-3Kg

g = 9.81 m/s2

ρ = 1000 kg/m3

d =?

d = [6(T + mg) /πρg]^1/3

d = [6(0.029 + 2.5x10^-3x9.81)/ πx1000x9.81]^1/3

d = 0.022m

Therefore, the diameter of the ball is 0.022m or 2.2cm

6 0

3 years ago

If 2 objects have the same momentum which statement is true

rewona [7]

The correct answer is B

8 0

3 years ago

Read 2 more answers