The initial volume of the gas is obtained as 11.02 L.
<h3>What is the initial volume?</h3>
The work done can be obtained from the use of the formula;
W = PΔV
W = work done on the gas
P = pressure of the gas
ΔV = Change in volume
Now we can see that;
Internal energy = 127.5 J or 1.26 Latm
Heat lost = 34.7 J or 0.34 Latm
We now have;
-1.26 = 0.34 - 0.900(12.80 - V1)
-1.26 = 0.34 - 11.52 + 0.9V1
-1.26 + 11.18 = 0.9V1
V1 = -1.26 + 11.18 / 0.9
V1 = 11.02 L
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The answer is c and possibly a I don't know why im here i dont know what this is so bye...
The partial pressure of the N2H4 gas is 1.50 atm.
<h3>Dalton's law of partial pressure</h3>
From the Dalton's law of partial pressure, the total pressure of a mixture of gases is the sum of the individual partial pressures of all the gases present in the mixture.
We have the following;
C2H2F4 = 3.00 atm
N2H4 = c
Total pressure = 3.00 atm + 1.50 atm = 4.50 atm
Hence, the partial pressure of the N2H4 is N2H4.
Learn more about partial pressure: brainly.com/question/14623719
