Given: Mass m = 5.00 Kg; Height h = 12 m; Time t = 15 s
Required: Power P = ?
Formula: P = Fd/t = mgh/t
P = (5.0 Kg)(9.8 m/s²)(12 m)/15 s
P = 39.2 Kg.m²/s² or
P = 39.2 J
The answer is B
I used these equations then i putted it together.
Charge = number of ( electron or proton ) x charge of ( electron or proton )
Force = k x (q1 q2)/r²
Notice that
<em>B</em> = 4<em>i</em> + 6<em>j</em> - 2<em>k</em> = 2 (2<em>i</em> + 3<em>j</em> - <em>k</em>) = 2<em>A</em>
so both vectors point in the same direction and the angle between them is (A) 0°.
Answer:
a) 323.4J
b) 0J
c) -323.4J
Explanation:
a) W=Fd
F=ma
solve for acc. using kinematics
v^2=vo^2+2a(x)
8.41=2a(12)
4.205=a(12)
0.35=a
F=(77)(0.35)
F=26.95N
W=26.95*12...... W=323.4J
b) No acceleration, thus no force, thus no work!
c) W=Fd
F=ma
find acc. using kinematics: v^2=vo^2+2a(x)
0=(2.9^2)+2a(12)
0=8.41+2a(12)
-8.41=2a(12)
-4.205=a(12)
-0.35=a
F=(77)(-0.35)
F=-26.95N
W=(-26.95)(12)
W=-323.4J
Yes, work can be negative!
Answer:
F_suv= 49050 N
Explanation:
We are told that a 2000 kg car moving down the road runs into a 5000 kg stationary suv. The car applies a force of 1400 N on the suv.
Now, according Newton's first law of motion, an object will continue in it's present state of rest except it is acted upon by an external body.
This means the force acting on the stationary Suv is force of gravity.
Thus; F_suv = 5000 × 9.81
F_suv= 49050 N
